Ask question

Ask question

All categories

3 years ago

6

A battery can run for 120 hours supplying a current of 148 milliamps mA. What is the capacity of the battery in amp-hours Ah? Th

ank you.

1 answer:

joja [24]3 years ago

8 0

120h -------- 140mAh
120h -------- 0,14Ah
1h -------- 0,14Ah*120
1h -------- 16,8Ah
<span>Answer: 16,8Ah.</span>

You might be interested in

WHOEVER ANSWERS CORRECT AND FAST WILL GET BRAINLIEST

amid [387]

Answer:

b

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

David had a bunch of grapes for his snack . If he at 0.1 of a pound every hour , how many pounds did he eat in a 4.4 hours ?

olga_2 [115]

0.44 lbs.
Is likely your answer

8 0

2 years ago

Read 2 more answers

Pip and Sara win some money and share it in ratio 5:4 pip gets £50 how much did they get all together

N76 [4]

Answer: £90

Step-by-step explanation:

Pip and Sara get some money. They share it in the ratio 5 : 4.

Pip gets £50 so what did Sara get:

Use direct proportion:

5 : 4

50 : x

5x = 200

x = 200/5

x = £40

Pip got £50 and Sara got £40.

Together they got:

= 50 + 40

= £90

4 0

2 years ago

The gross domestic product is?

scZoUnD [109]

Gross domestic product (GDP) is the total monetary or market value of all the finished goods and services produced within a country's borders in a specific time period. As a broad measure of overall domestic production, it functions as a comprehensive scorecard of a given country's economic health.

8 0

2 years ago

Read 2 more answers

A circle is growing so that the radius is increasing at the rate of 3 cm/min. How fast is the area of the circle changing at the

Naya [18.7K]

Answer:

The area is growing at a rate of $\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}$

Step-by-step explanation:

<em>Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.</em>

We identify that the info given on the increasing rate of the circle's radius is 3 $\frac{cm}{min}$ and we identify such as the following differential rate:

$\frac{dr}{dt} = 3\,\frac{cm}{min}$

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find $\frac{dA}{dt}$ .

So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

$A=\pi\,r^2$

We now apply the derivative operator with respect to time ( $\frac{d}{dt}$ ) to this equation, and use chain rule as we find the quadratic form of the radius:

$\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}$

Now we replace the known values of the rate at which the radius is growing ( $\frac{dr}{dt} = 3\,\frac{cm}{min}$ ), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

$\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}\\\frac{dA}{dt} =\pi\,*2*(12\,cm)*(3\,\frac{cm}{min}) \\\frac{dA}{dt} =226.19467 \,\frac{cm^2}{min}\\$

which we can round to one decimal place as:

$\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}$

4 0

3 years ago