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erma4kov [3.2K]
2 years ago
14

Express in exponential form. log2(x)=3

Mathematics
1 answer:
igomit [66]2 years ago
3 0
The relationship between logarithms and exponentials is that they are inverses of each other. That is, they are reflected about the line y = x.
In order to rewrite logarithms, we need to understand the basic fundamentals of them:
log_ab = y

This is essentially saying: "If we raise a to the y-th power, we get the answer to b".
Using this, we can say:
log_2x = 3 \rightarrow 2^{3} = x
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Please help me!!! :D
lesantik [10]

Explanation:

For a theorem that says "if A then B", the converse is "if B then A."

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The hing.e theorem has numerous parts to the hypothesis. Its converse retains many of those conditions, swapping only the relation between the included angle and the third side.

<u>theorem</u>: if two sides of one triangle are congruent to two sides of another, then the longest third side will be opposite the largest included angle.

<u>converse</u>: if two sides of one triangle are congruent to two sides of another, then the largest included angle will be opposite the longest third side.

Instead of relating the third side to the angle measure, the converse relates the angle measure to the third side.

4 0
2 years ago
The following table shows a proportional relationship between x and y.
RUDIKE [14]

Answer:

Assume x is directly proportional to y :

y \:  \alpha  \: x \\ y = kx

when y is 9, x is 2:

substitute to find value of k :

9 = (k \times 2) \\ k =  \frac{9}{2}

Therefore, equation is:

{ \boxed{ \boxed{2y = 9 x}}}

8 0
2 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
Please answer need help
12345 [234]

Answer: The third one is the correct answer

Step-by-step explanation: I hope this helps

4 0
2 years ago
Read 2 more answers
What is the annual interest rate is 1=$160.67, p=$2000, t=8 months
Sergeeva-Olga [200]
Please use " i " to denote "interest."

the formula for simple interest is i = p r t.

Here, i = $160.67 = $2000 (r) (8/12)


Solving for the interest rate, r = ($169.67)(12/8)/ $2000 = 0.127, or 12.7%
4 0
3 years ago
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