Mass of methane takne = 1.5g
moles of methane used = masss / molar mass = 1.5 / 16 = 0.094 moles
mass of water = 1000 g
Initial temperature of water = 25 C
final temperature = 37 C
specific heat of water = 4.184 J /g C
1) Heat absorbed by water = q =m• C• ΔT = 1000 X 4.184 x (37-25) = 50208 Joules
2) Heat absorbed by calorimeter = Heat capacity X ΔT = 695 X (37-25) = 8340 J
3) Total heat of combustion = heat absorbed by water + calorimeter = 50208 + 8340 = 58548 Joules
This heat is released by 0.094 moles of methane
So heat released by one mole of methane =
- 622851.06 Joules = 622.85 kJ / mole
4) standard enthalpy of combustion = -882 kJ / mole
Error = (882-622.85) X 100 / 882 = 24.84 %
Answer:
Ionization energy is the energy required to remove an electron away from an atom, which can be written as IE. ... Electron affinity, on the other hand, is the energy released when an electron is added to the atom. On the periodic table, electron affinity usually decreases down a group, and increases across a period.
Explanation:
Answer:
0,33atm
Explanation:
For the reaction:
NH₄HS(s) ⇌ H₂S(g) + NH₃(g)
kp is defined as:
kp = 0.11 = P(H₂S) P(NH₃) <em>(1)</em>
Where P(H₂S) and P(NH₃) are partial pressures of each compound.
In equilibrium, if in your system the only addition is of NH₄HS(s), the partial pressures and the concentration of each compound are:
NH₄HS: I - x
<em>-Where I is an initial concentration that is not relevant for the problem and x is the </em>NH₄HS<em> that reacts-</em>
H₂S(g): x
NH₃(g): x
Replacing in (1):
0.11 = X×X
0.11 = X²
<em>0.33 = X</em>
That means P(NH₃) is <em>0.33 atm</em>
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I hope it helps!
A.Volume
Explanation:
because the basic formula for Volume is =Length×width×height
Another example of a length derivative is Area (length × width)