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wlad13 [49]
3 years ago
10

How are the terms "ionization energy" and "electron affinity" related to each other?

Chemistry
1 answer:
podryga [215]3 years ago
6 0

Answer:

Ionization energy is the energy required to remove an electron away from an atom, which can be written as IE. ... Electron affinity, on the other hand, is the energy released when an electron is added to the atom. On the periodic table, electron affinity usually decreases down a group, and increases across a period.

Explanation:

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An 80.0-gram sample of water at 10.0°C absorbs 1680 Joules of heat energy. What is the final temperature of the water? a 50.0°C
ICE Princess25 [194]

Answer:

b)15.0°C

Explanation:

Specific Heat of Water=4.2 J/g°C

This means, that 1 g of Water will take 4.2 J of energy to increase its temperature by 1°C.

∴80 g Water will take 80×4.2 J of energy to increase its temperature by 1°C.

80×4.2 J=336 J

Total Energy Provided=1680 J

The temperature increase=\frac{\textrm{Total energy required}}{\textrm{energy required to increase temperature by one degree}}

Temperature increase=\frac{1680}{336}

=5°C

Initial Temperature =10°C

Final Temperature=Initial + Increase in Temperature

=10+5=15°C

7 0
3 years ago
What is the mass in grams of 2.0 moles of NO2
JulsSmile [24]
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1 mole -------- 46.0 g
2.0 moles ----- ?

Mass (NO₂) = 2.0 x 46.0 / 1

=> 92.0 g

hope this helps!
8 0
4 years ago
Read 2 more answers
Calculate the pH of the solutions: [H^+]= 1.6 x 10^-3 M
Yuliya22 [10]

Answer:

A) pH = 2.8

B) pH = 5.5

C) pH = 8.9

D) pH = 13.72

Explanation:

a) [H⁺]  = 1.6 × 10⁻³ M

pH = -log [H⁺]

pH = -log [1.6 × 10⁻³ ]

pH = 2.8

b) [H⁺]  = 3 × 10⁻⁶

pH = -log [H⁺]

pH = -log [3 × 10⁻⁶ ]

pH = 5.5

c) [OH⁻] = 8.2 × 10⁻⁶

pOH = -log[OH]

pOH = -log[8.2 × 10⁻⁶]

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d) [OH⁻] = 0.53 M

pOH = -log[OH]

pOH = -log[0.53]

pOH = 0.28

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 0.28

pH = 13.72

5 0
4 years ago
Which expression is equal to the number of grams in 2.43 kilograms
KiRa [710]
1 kg = 1000g
2.43 kg *1000g/1kg = 2430 g
3 0
4 years ago
How are properties useful in classifying materials
lukranit [14]
S. Properties can be anything from composition to color to ductility. Without knowing an object's properties, it is impossible to characterize it. For example, looking at some common properties of metals helps to differentiate them from non-metals or metalloids.
5 0
4 years ago
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