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3 years ago

What term refers to columns of elements?

Chemistry

1 answer:

Ira Lisetskai [31]3 years ago

8 0

The term is group
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In a strong acid–strong base titration (both monoprotic), if 25.0 milliliters of the base is required to completely neutralize 2

taurus [48]

B)The concentration of the acid (C₁) is the same as that of the base (C₂).

V₁=V₂

n(acid)=C₁V₁
n(base)=C₂V₂

HX + YOH = YX + H₂O

n(acid)=n(base)

C₁V₁=C₂V₂

C₁=C₂

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3 years ago

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At what point in time (A ,B or C) is the reaction the fastest? How do you know?

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3 years ago

Two different bromide solutions are mixed with each other: Solution 1 is an aqueous solution of 4.85 g aluminum bromidein 150. m

erma4kov [3.2K]

Answer:

M=0.380 M.

Explanation:

Hello there!

In this case, given those two solutions of aluminum bromide and zinc bromide, it is firstly necessary to compute the moles of bromide ions in each solution as shown below:

$n_{Br^-}^{in\ AlBr_3}=4.85 gAlBr_3*\frac{1molAlBr_3}{266.69gAlBr_3}*\frac{3molBr^-}{1molAlBr_3} =0.05456molBr^-\\\\n_{Br^-}^{in\ ZnBr_2}=7.75gZnBr_2*\frac{1molZnBr_2}{225.22gZnBr_2}*\frac{2molBr^-}{1molZnBr_2} =0.06882molBr^-$

Now, we compute the total moles of bromide:

$n_{Br^-}=0.05456mol+0.06882mol\\\\n_{Br^-}=0.12338mol$

Then, the total volume in liters:

$150mL+175mL=325mL*\frac{1L}{1000mL} \\\\=0.325L$

Therefore, the concentration of total bromide is:

$M=\frac{0.12338mol}{0.325L}\\\\M=0.380M$

Best regards!

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2 years ago

How many moles of iron can be produced from 4.20 moles of iron (III) oxide?

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3 years ago

What organelle or organelles store food or pigments

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A.chlorophyll plastid,ribosome,rough endoplasmic reticulum. B.green pigment that absorbs light for photosynthesis, a plant cell structure that stores food of contain pigments, the construction site for protein s ribosomes can be found in the surface of this organelle.

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3 years ago