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3 years ago

9

Is the sequence 0, 4, 16, 36, 64 linear or exponential

1 answer:

Blababa [14]3 years ago

8 0

Answer:

It is Linear.... since it's just multiplying by 2 but not by the same number

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Express the statement "A rectangular field with an area of 120m' has it length 12mn longer than the width" as quadratic equation

navik [9.2K]

Answer:

The quadratic equation is x^2 -12x -120 = 0

where x represents the length of the field

Step-by-step explanation:

We want to make an expression in terms of a quadratic equation;

Let the length of the field be x mm , then the width will be (x-12) mm

Mathematically , the area of the field will be L * B

Thus;

x * (x-12) = 120

That gives;

x^2 -12x = 120

x^2 -12x -120 = 0

6 0

3 years ago

Which statement is true?

WITCHER [35]

Answer: bro its the last one

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

What is the volume of a rectangular prism with the following dimensions

andriy [413]

Answer: 250ft3

Step-by-step explanation:

v=l*w*H

v= 10*5 * 5

v=250

7 0

3 years ago

Read 2 more answers

Wegnerkolmp or someone who can explain maths please<br> I need a proper explanation

umka2103 [35]

Answer: 66 degrees

Explanation:

Check out the attached image below. Figure 1 is the original image without any additions or alterations. Then in figure 2, I extend segment BC to form a line going infinitely in both directions. This line crosses segment DE at point F as shown in the second figure.

Note how angles ABC and DFC are alternate interior angles. Because AB is parallel to DE (given by the arrow markers) this means angle DFC is also 24 degrees

Focus on triangle DFC. This is a right triangle. The 90 degree angle is at C.

So we know that the acute angles x and 24 are complementary. They add to 90. Solve for x

x+24 = 90

x+24-24 = 90-24

x = 66

That is why angle CDE is 66 degrees

6 0

3 years ago