Answer:
cos(O) = 39 / 89
Step-by-step explanation:
Given:
ΔOPQ, where
∠Q=90°
PO = 89
OQ = 39
QP = 80
cosine of ∠O?
cos(O) = Adjacent / Hypotenuse
cos(O) = 39 / 89
Answer:
10feet
Step-by-step explanation:
We solve this question, using Pythagoras Theorem to solve for the other side.
Pythagoras Theorem states that
c² = a² + b²
c = √(a² + b²)
In the question, a = 6 feet
b = 8 feet
c = length of the rope
c = √6² + 8²
c = √36 + 64
c = √100
c = 10 feet
The length of the rope is 10 feet
Answer:
c
Step-by-step explanation:
Answer:480
Step-by-step explanation:
12,000 Divided by 25 = 480
<span>Let's find out the ball's acceleration
V^2 = U^2 + 2as
Where the distance S = 6 feet and U = 45.
Suppose he just took off so V = 0 and we are left with U^2 =2as
(45)^2 = 2a(6)
a = 2025/12 = 168.75 ft/s^2
Also S = ut + 1/2 at^2
Here S = 5ft and U= 0; a = 168.75. So we have 5 = (1/2) * 168.75 * t^2
So we have 5 * 2 = 168.75 t^2
T^2 = âš 10/ 168.75 = 0.00596 = âš0.006
T = 0.0077s</span>
