Trigonometric ratios in right triangles pls help

F(x)=2x+4 when domain is {-2,0,3}

anzhelika [568]

Step-by-step explanation:

The domain is x. The range is y (or in this case F(x)).

Plug in the numbers in the number set to get a number set for your y.

When the domain is -2:

f(-2) = 2(-2) + 4

f(-2) = -4 + 4

f(-2) = 0

When the domain is -2, the range is 0.

(-2 , 0)

When the domain is 0:

f(0) = 2(0) + 4

f(0) = 0 + 4

f(0) = 4

When the domain is 0, the range is 4.

(0 , 4)

When the domain is 3:

f(3) = 2(3) + 4

f(3) = 6 + 4

f(3) = 10

When the domain is 3, the range is 10.

(3 , 10)

4 0

3 years ago

What is the equation of a line containing the points (-3,2) and (-2,-1)

sasho [114]

-3 over 1 is the answer

7 0

3 years ago

Read 2 more answers

How do I find the value of a in 30=5a

Sav [38]

Answer:

a = 30/5 = 6

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

About 33% of people who get their feet examined are found to have an ingrown toenail. What is the probability of a podiatrist ex

enot [183]

Answer:

The correct answer is 0.94147

Step-by-step explanation:

Let A denote the event that the podiatrist finds the first person with an ingrown toenail.

And (1 - A) denote the event that the podiatrist does not find the ingrown toenail.

While examining seven people, the podiatrist can find the very first person to have an ingrown toenail. Similarly he can find the second patient to have the ingrown toenail. Going in this way the probability of the first person to have an ingrown toenail is given by:

= A + (1 - A) × A + (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A.

= $\frac{1}{3} + \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} .$

= $\frac{1}{3} + \frac{2}{3} \frac{1}{3} + (\frac{2}{3}) ^{2} \frac{1}{3} + (\frac{2}{3})^{3} \frac{1}{3} + (\frac{2}{3})^{4} \frac{1}{3} + (\frac{2}{3})^{5} \frac{1}{3} + (\frac{2}{3})^{6} \frac{1}{3}.$

= 0.94147

We can also solve the above expression by using the geometric progression formula as well where common ratio is given by $\dfrac{2}{3}$ .

8 0

3 years ago

What is x+4y=6 and y=-x+3 substituted

zavuch27 [327]

If x + 4y = 6 and you subst. -x+3 for y, you get x + 4(-x+3) = 6.

Then x - 4x + 12 = 6, or -3x = -6, or x = 2. Since y = -x+3, here y = -(2)+3 = 1.

Thus, the solution to this system of linear equations is (2,1).

5 0

3 years ago