Colby starts with 50 bacteria in his culture and the number of bacteria doubles every 2 hours, and Jaquan starts with 80 bacteri
a that double every 3 hours. x= number of DAYS. Would Colby's experiment be modeled by... y=50(2)^x y=50(2)^8x or y=50(2)^12x Would Jaquan's experiment be modeled by... y=80(2)^x y=80(2)^8x or y=80(2)^12x
Given that x=number of days To model the expressions we use the exponential growth given by: y=a(b)^nx where: a=initial value b=growth factor n=24 hours thus Colby's experiment will be: y=50(2)^(1/2*24*x) y=50(2)^(12x) N/B we multiply by 24 so as to convert days into hours
b] <span>Jaquan's starts with 80 bacteria that double every 3 hours. a=80, b=2 thus y=80(2)^(1/3</span>×24×x<span>) simplifying the above we get: y=80(2)^(8x)</span>