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3 years ago

When to fractions are between 0 1/2 how do you know which fraction is greater explain

1 answer:

5 0

By creating a common denominator, you can compare different numbers to the same ratio. For example:
Take 2/3 and 3/4
Now 3/4 is the same as 9/12
And 2/3 is the same as 8/12
Now that they have the same denominator, you can tell that 9/12 is clearly greater than 8/12, meaning 3/4 is greater than 2/3.

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James has 3 pairs of running shoes for every 4 pairs of basketball shoes. If he has 12 pairs of basketball shoes, how many pairs

GaryK [48]

If James has 12 pairs of basketball shoes, then the ratio would be 3:4 which would stop at 3:12. Then the individual ratios would be 3:4, 6:8, and 9:12

So James has 9 pairs of running shoes

7 0

3 years ago

Richard has just been given an l0-question multiple-choice quiz in his history class. Each question has five answers, of which o

myrzilka [38]

Answer:

a) 0.0000001024 probability that he will answer all questions correctly.

b) 0.1074 = 10.74% probability that he will answer all questions incorrectly

c) 0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

d) 0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he answers it correctly, or he does not. The probability of answering a question correctly is independent of any other question. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Each question has five answers, of which only one is correct

This means that the probability of correctly answering a question guessing is $p = \frac{1}{5} = 0.2$

10 questions.

This means that $n = 10$

A) What is the probability that he will answer all questions correctly?

This is $P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} = 0.0000001024$

0.0000001024 probability that he will answer all questions correctly.

B) What is the probability that he will answer all questions incorrectly?

None correctly, so $P(X = 0)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074$

0.1074 = 10.74% probability that he will answer all questions incorrectly

C) What is the probability that he will answer at least one of the questions correctly?

This is

$P(X \geq 1) = 1 - P(X = 0)$

Since $P(X = 0) = 0.1074$ , from item b.

$P(X \geq 1) = 1 - 0.1074 = 0.8926$

0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

D) What is the probability that Richard will answer at least half the questions correctly?

This is

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{10,5}.(0.2)^{5}.(0.8)^{5} = 0.0264$

$P(X = 6) = C_{10,6}.(0.2)^{6}.(0.8)^{4} = 0.0055$

$P(X = 7) = C_{10,7}.(0.2)^{7}.(0.8)^{3} = 0.0008$

$P(X = 8) = C_{10,8}.(0.2)^{8}.(0.8)^{2} = 0.0001$

$P(X = 9) = C_{10,9}.(0.2)^{9}.(0.8)^{1} \approx 0$

$P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} \approx 0$

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0264 + 0.0055 + 0.0008 + 0.0001 + 0 + 0 = 0.0328$

0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

8 0

3 years ago

The table below represents the closing cost of ABC for the last 5 days. What is the r -value of the linear regression that fits

Gnoma [55]

Answer:

The correct option is D.

Step-by-step explanation:

The linear regression equation is in the form of

$y=bx+a$

Where,

$b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}$

$a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}$

The formula of r is

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n(\sum x^2)-(\sum x)^2][n(\sum y^2)-(\sum y)^2]}}$

The values are

$\sum x=15,\sum y=98.91,\sum x^2=55,\sum y^2=1957.8295,\sum xy=293.78, n=5$

Using above formula, we get

$r=-0.85650$

Therefore option D is correct.

3 0

3 years ago

Read 2 more answers

Colins class had 15 girls and 12 boys. If there were 4 boys what would be an equivalent ratio of boys and girls?

Leni [432]

Answer:

there would be 5 girls, boys 1; girl 1.25

Step-by-step explanation:

there are 1.25 girls for every boy

8 0

3 years ago

Uh yall know the answer?

olga_2 [115]

Answer:

pizza?

Step-by-step explanation:

tbh I'm confused soooo

6 0

3 years ago

Read 2 more answers