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lukranit [14]
4 years ago
10

The activation energy for a(n) _____ is quite large and usually takes extra energy from the environment, it is normally not a na

tural spontaneous process.
combustion reaction
endothermic reaction
exothermic reaction
catalyzed reaction
Chemistry
2 answers:
Mariulka [41]4 years ago
5 0

The given blank can be filled with endothermic reactions.  

The endothermic reactions or processes captivates energy from its surroundings, primarily, but will not always be in the form of heat. A reaction, which requires the input of energy that dissociates a bond will always be endothermic. The best examples of endothermic reactions are evaporation of the liquid, melting cubes, melting or solid salts, and others.  


Marina CMI [18]4 years ago
5 0

Answer:

endothermic reaction

Explanation:

Endothermic reaction takes place when heat is absorbed from the surrounding.  Exothermic reaction takes place when heat is released into the surrounding.  Catalyzed reaction takes place only in the presence of a catalyst. The role of a catalyst is to lower the activation of a reaction and accelerates the rate of the reaction. In a combustion reaction hydrocarbon in the presence of oxygen produces carbon dioxide and water.

As endothermic reaction requires high heat to start the process is nonspontaneous.

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3 years ago
Consider the reaction 2N2(g) O2(g)2N2O(g) Using the standard thermodynamic data in the tables linked above, calculate Grxn for t
ratelena [41]

Answer:

\Delta G^0 _{rxn} = 207.6\ kJ/mol

ΔG ≅ 199.91 kJ

Explanation:

Consider the reaction:

2N_{2(g)} + O_{2(g)} \to 2N_2O_{(g)}

temperature = 298.15K

pressure = 22.20 mmHg

From, The standard Thermodynamic Tables; the following data were obtained

\Delta G_f^0  \ \ \ N_2O_{(g)} = 103 .8  \ kJ/mol

\Delta G_f^0  \ \ \ N_2{(g)} =0 \ kJ/mol

\Delta G_f^0  \ \ \ O_2{(g)} =0 \ kJ/mol

\Delta G^0 _{rxn} = 2 \times \Delta G_f^0  \ N_2O_{(g)} - ( 2 \times  \Delta G_f^0  \ N_2{(g)} +   \Delta G_f^0  \ O_{2(g)})

\Delta G^0 _{rxn} = 2 \times 103.8 \ kJ/mol - ( 2 \times  0 +   0)

\Delta G^0 _{rxn} = 207.6\ kJ/mol

The equilibrium constant determined from the partial pressure denoted as K_p can be expressed as :

K_p = \dfrac{(22.20)^2}{(22.20)^2 \times (22.20)}

K_p = \dfrac{1}{ (22.20)}

K_p = 0.045

\Delta G = \Delta G^0 _{rxn} + RT \ lnK

where;

R = gas constant = 8.314 × 10⁻³ kJ

\Delta G =207.6 + 8.314 \times 10 ^{-3} \times 298.15  \ ln(0.045)

\Delta G =207.6 + 2.4788191 \times \ ln(0.045)

\Delta G =207.6+ (-7.687048037)

\Delta G = 199.912952  kJ

ΔG ≅ 199.91 kJ

7 0
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Mag aral ka muna bago ml
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What is the mass of 48 ml of a liquid if its density is 1.25 g/ml?
soldi70 [24.7K]

Answer:

60 g

Explanation:

Mass = Density × Volume

Mass = 1.25 × 48

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I hope this helps!

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3 waves are shown with a line through their center. The bottom of the first wave is labeled C. A bracket labeled D connects the
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