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Goshia [24]
3 years ago
12

The chemical equation below shows the combustion of methane (CH4).

Chemistry
2 answers:
Vikki [24]3 years ago
8 0

Answer:

B. 6.15

Explanation:

pishuonlain [190]3 years ago
3 0
According to the chemical equation, the reaction ratio between O2 and CO2 is 2:1, which mean for every 2 moles of O2 reacted there is 1 mole of CO2 formed. 

Use the molar mass and mass of O2 to find out the moles of O2: moles of O2 = mass of O2/molar mass of O2 = 8.94g/32.00g/mol = 0.2794 mole.  Therefore, the moles of CO2 that formed is 0.2794moles/2 = 0.1397 mole

Use the moles and molar mass CO2 to find out the mass of CO2:
Mass of CO2 = moles of CO2 * molar mass of CO2 = 0.1397 mole * .44.01g/mole = 6.15 g.

So the answer is B 6.15g.
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What is the volume of 2.00 moles of ideal gas at 25'c and 121.59 kpa of pressure
katrin [286]

Answer:

40.73 L.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm (P = 121.59 kPa/101.325 = 1.2 atm).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = 2.0 mol).

R  is the general gas constant (R = 0.082 L.atm/mol.K),

T is the temperature of the gas in K (T = 25°C + 273 = 298 K).

<em>∴ V = nRT/P</em> = (2.0 mol)(0.082 L.atm/mol.K)(298 K)/(1.2 atm) = <em>40.73 L.</em>

6 0
3 years ago
Why does hydrochloric acid have a higher boiling point than diatomic fluorine? The stabilizing effect of dipole interactions in
il63 [147K]
The correct answer would be the fourth option. Hydrochloric acid has a higher boiling point than fluorine molecule because the former is a polar molecule which means that it has stronger bonds than fluorine which is a non-polar molecule. Stronger bonds require more energy to break these bonds.
6 0
3 years ago
Read 2 more answers
Which causes genetic variations and can result in different alleles? O predation rate O random mutations O competition o environ
alekssr [168]

Answer:

B

Explanation:

3 0
3 years ago
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What is the concentration of a 1:10 dilution of a 2.5 M solution of NaCl? How would you prepare exactly 100 ml of such a solutio
Marina CMI [18]

<u>Answer:</u> The concentration of the solution is 0.25 M

<u>Explanation:</u>

Let the volume of solution of 2.5 M NaCl be 10 mL

We are given:

Dilution ratio = 1 : 10

So, the solution prepared will have a volume of = \frac{10}{1}\times 1000=100mL

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated NaCl solution

M_2\text{ and }V_2 are the molarity and volume of diluted NaCl solution

We are given:

M_1=2.5M\\V_1=10mL\\M_2=?M\\V_2=100mL

Putting values in above equation, we get:

2.5\times 10=M_2\times 100\\\\M_2=\frac{2.5\times 10}{100}=0.25M

Hence, the concentration of the solution is 0.25 M

6 0
4 years ago
PLEASE HELPPPP!!! IM BEING TIMED
Mrac [35]

Answer:

B)

Explanation:

This should be the correct answer, lmk if it's not

8 0
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