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3 years ago

The 3 types of heat transfer are convection, radiation, connected. A. True B. False

Chemistry

1 answer:

frez [133]3 years ago

4 0

False. They are Convection, Conduction, and Radiation.

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A single atom of an element has 21 neutrons, 20 electrons, and 20 protons. Which element is it?

sukhopar [10]

Answer:

Explanation:

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3 years ago

Name the following: Simple chemical molecules made of single unit

Stolb23 [73]

Answer:

atom is the answer I think

7 0

3 years ago

Which statement is true about the patterns shown on the electromagnetic spectrum?

Rudiy27

A. As wavelength increases, radiant energy and frequency increase.

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2 years ago

Methyl salicylate is a common active ingredient in liniments such as ben-gay. It is also known as oil of wintergreen. It is made

arlik [135]

Answer: The empirical formula is $C_3H_3O$ .

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2$ = 12.24 g

Mass of $H_2O$ = 2.505 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 12.24 g of carbon dioxide, = $\frac{12}{44}\times 12.24=3.338g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 2.505 g of water, = $\frac{2}{18}\times 2.505=0.278g$ of hydrogen will be contained.

Mass of oxygen in the compound = (5.287) - (3.338+0.278) = 1.671 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{3.338g}{12g/mole}=0.278moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.278g}{1g/mole}=0.278moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{1.671g}{16g/mole}=0.104moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.278}{0.104}=3$

For H = $\frac{0.278}{0.104}=3$

For O = $\frac{0.104}{0.104}=1$

The ratio of C : H : O = 3: 3: 1

Hence the empirical formula is $C_3H_3O$ .

5 0

3 years ago

If 50.75 g of a gas occupies 10.0 l at stp, 129.3 g of the gas will occupy __________ l at stp.

Rom4ik [11]

Use PV = mRT/M and solve for R. R = PVM/RT. Since you have the same gas under two sets of conditions then you can write
P1V1M1/m1T1 = P2V2M2/m2T2 
Since P, M and T are constant, the equation becomes 
V1/m1 = V2/m2 
Now plug in your values and solve for V2

6 0

3 years ago

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