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topjm [15]
3 years ago
13

125 thousandths = 1 tenth and ______ thousandths..... HELP

Mathematics
1 answer:
Evgen [1.6K]3 years ago
3 0
125 thousandths is the same as .125
Since decimals go tenths, hundredths, thousandths......
you would just say how many this decimal has, so it has 1tenth and 25 thousandths. 

 
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Write a polynomial to represent the value of d dimes and n nickels.
nadya68 [22]
Answer: 0.10d + 0.05n
Note: this value expression is in dollars (not cents)
If you want the expression in cents instead of dollars, then it would be 10d+5n

--------------------------------------------------------------------------------

The value of just the dimes only is 0.10d dollars
The value of just the nickels only is 0.05n dollars
Combined the total value is 0.10d+0.05n dollars
3 0
3 years ago
8x-5y=21 simultaneous linear equation<br>2x+9y=-5
olya-2409 [2.1K]

Answer:

x=2 and y=-1

Step-by-step explanation:

If two equations are given, we can solve one of the equation in terms of single variable and put it in the other equation which will further give the value of x and y.

For the given equations:

8x-5y=21              Equation:1

2x+9y=-5             Equation:2

Solving equation multiply equation 2 with 4 on both the sides

8x+36y=-20        Equation 3

Subtracting Equation:3 from Equation:1

8x-5y-(8x+36y)=21-(-20)\\8x-5y-8x-36y=21+20\\-41y=41\\y=-1

Putting value of 'y' in Equation:2 which will give the value of x

2x+9y=-5\\2x+9(-1)=-5\\2x-9=-5\\2x=4\\x=2

8 0
3 years ago
Factored form of 16m^4-121
AnnZ [28]

16m^4-121 =(4m^2-11)(4m^2+11)

8 0
3 years ago
What is the surface area of this square pyramid
JulsSmile [24]

Answer:

Surface area of square pyramid shown in picture:

A = area of 4 triangles + area of square

  = 4 x 4 x 3 x (1/2) + 3 x 3

  = 33 (ft)

=> Option 4 (last one) is correct

Hope this helps!

:)

3 0
3 years ago
Devaughn is 6 years younger than Sydney. The sum of their ages is 50 . What is Sydney's age?
dedylja [7]
Sydney is 44 years old.
50-6=44
Hope i helped.

Mark as brainliest
7 0
4 years ago
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