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valentina_108 [34]
3 years ago
5

The rate of a reaction is the speed at which products form or reactants disappear. T/F

Physics
1 answer:
Natali [406]3 years ago
3 0

Answer: TRUE (:

Explanation:

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a satellite maintains an orbit equidistant from the earth at all points along its orbital path hiw is the satellite affected by
Paraphin [41]
ANY closed orbit exists because of the centripetal force of gravity.
Without the force of gravity, the satellite would simply sail away
in a straight line.

The orbit you're describing happens to be a circular orbit, but it
doesn't have to be circular.
5 0
4 years ago
Explain how the graphic organizer helped you formulate your decision and participate in the discussion.
nekit [7.7K]

Answer:

The graphic organizers help to keep track of the details. They are a visual representation of knowledge that rescue the important aspects of a concept using labels within a scheme. They also present information in a concise manner, highlighting the organization and the relationship of the concepts. Graphic organizers help students organize their thinking process and their writing.

Explanation:

6 0
3 years ago
A rectangular plate has a length of (21.7 ± 0.2) cm and a width of (8.2 ± 0.1) cm. Calculate the area of the plate, including it
Grace [21]

Answer:

(177.94 ± 3.81) cm^2

Explanation:

l + Δl = 21.7 ± 0.2 cm

b + Δb = 8.2 ± 0.1 cm

Area, A = l x b = 21.7 x 8.2 = 177.94 cm^2

Now use error propagation

\frac{\Delta A}{A}=\frac{\Delta l}{l}+\frac{\Delta b}{b}

\frac{\Delta A}{A}=\frac{0.2}{21.7}+\frac{0.1}{8.2}

\Delta A=177.94 \times \left ( 0.0092 + 0.0122 \right )=3.81

So, the area with the error limits is written as

A + ΔA = (177.94 ± 3.81) cm^2

8 0
3 years ago
A pendulum makes 40 vibrations in 20 seconds. calculate it's period?
DiKsa [7]

(20 seconds / 40 vibes) = (20/40) (seconds/vibe) =  0.5 second
3 0
4 years ago
Read 2 more answers
2. Two charged particles as shown in figure below. QP = +10 μC and Qq = +20 μC are separated by a distance r = 10 cm. What is th
netineya [11]

Answer:

F = 180 N

Explanation:

Given that,

Charge, q₁ = 10 μC

Charge, q₂ = 20 μC

The distance between the charges, r = 10 cm = 0.1 m

We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :

F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 10\times 10^{-6}\times 20\times 10^{-6}}{(0.1)^2}\\F=180\ N

So, the magnitude of the electrostatic force is 180 N.

4 0
3 years ago
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