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jeyben [28]
3 years ago
9

Describe the difference between the velocity graph made walking at a steady rate and the velocity graph made at an increasing ra

te.
Physics
1 answer:
levacccp [35]3 years ago
8 0

Answer:

The difference between the velocity graph made walking at a steady rate means that its the same value in time, that means there's no slope on the graph, so its acceleration is 0

On the other hand, if the velocity is increasing with time, the slope of the graph becomes positive, which means that the acceleration of the particle is positive.

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3 years ago
Why do ice cubes always float at the top of a glass of water?
AnnZ [28]

Because water is a very very very very very unusual substance ... It's
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5 0
2 years ago
Read 2 more answers
A charged particle of mass 0.0050 kg is subjected to a 5.0 T magnetic field which acts at a right angle to its motion. If the pa
Irina18 [472]

Answer:

0.01 C

Explanation:

Applying,

F = qvBsinФ................ Equation 1

Where F = Force on the charged particle, q = charge on the particle, v = velocity, B = magnetic field, Ф =  angle

Since the charged particle noves in a circle,

F = mv²/r................. Equation 2

Where m = mass of the particle, v = velocity of the particle, r = radius of the  circle

Substitute equation 2 into equation 1

mv²/r = qvBsinФ

make q the subject of the equation

q = mv/(rBsinФ)............. Equation 3

Given: m = 0.005 kg, v = 2 m/s, r = 0.2 m, B = 5 T, Ф = 90° (Act at right angle)

Substitute these values into equation 3

q = (0.005×2)/(0.2×5×sin90°)

q = 0.01/(1)

q = 0.01 C

5 0
3 years ago
Sodium and potassium are positively charged ions called cations, and chloride and phosphate form negatively charged ions called
Alecsey [184]
 Sodium and potassium are positively charged ions called cations, and chloride and phosphate form negatively charged ions called anions. is true!

7 0
3 years ago
Block A weighs 14 lb and block B weighs 5 lb If B is moving downward with a velocity (vB)1 = 3 ft/s at t = 0, determine the velo
kolezko [41]

Velocity, va2 = 10.5 ft/s

<u>Explanation:</u>

From the figure:

Length of the cable = Sa + 2Sb = l

∴ vₐ = -2vb

Applying the principle of Impulse and momentum in x-direction

mv_x_1 + \int\limits^t_t {F_x} \, dt = mv_x_2

Limit is t1 to t2

-(\frac{14}{32.2}) (2) (3) - T = \frac{14}{32.2} v_y_2                           -(1)

Applying the principle of Impulse and momentum in y-direction

mv_y_1 + \int\limits^t_t {F_y} \, dt = mv_y_2

Limit is t1 to t2

(\frac{5}{32.2}) (3) - 2T + 3 = -\frac{5}{32.2} \frac{v_y_2}{2}                            -(2)

Solving equation (1) and (2), we obtain

T = 1.6lb

va2 = 10.5 ft/s

8 0
3 years ago
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