A bowling ball of mass 5 kg hits a wall going 7 m/s and rebounds at a speed of 2 m/s. What was the impulse applied to the bowlin

Question

3 years ago

6

g ball

2 answers:

LekaFEV [45] · Answer 1 · 2022-03-21T23:16:10+03:00

6 0

The impulse applied to the bowling ball is 45 kg m/s

gizmo_the_mogwai [7] · Answer 2 · 2022-03-22T01:00:05+03:00

3 0

Explanation :

Given that,

Mass of the ball, m = 5 kg

Initial velocity of the ball, u = 7 m/s

Final speed of the ball, v = 2 m/s

We know that the impulse applied to an object is equal to the change in momentum.

$J=\Delta p$

$J=p_f-p_i$

$J=m(v-u)$

$J=5\ kg(2\ m/s-7\ m/s)$

J = -25 kgm/s

Hence, this is the required solution.