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Leto [7]
3 years ago
6

A bowling ball of mass 5 kg hits a wall going 7 m/s and rebounds at a speed of 2 m/s. What was the impulse applied to the bowlin

g ball
Physics
2 answers:
LekaFEV [45]3 years ago
6 0
The impulse applied to the bowling ball is 45 kg m/s
gizmo_the_mogwai [7]3 years ago
3 0

Explanation :

Given that,

Mass of the ball, m = 5 kg

Initial velocity of the ball, u = 7 m/s

Final speed of the ball, v = 2 m/s

We know that the impulse applied to an object is equal to the change in momentum.

J=\Delta p

J=p_f-p_i

J=m(v-u)

J=5\ kg(2\ m/s-7\ m/s)

J = -25 kgm/s

Hence, this is the required solution.

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6 0
3 years ago
Which measurement tool is used to find the volume of a small piece of granite? Select one: a. thermometer b. metric ruler c. gra
Natalka [10]

Answer:

Explanation:

c. graduated cylinder

3 0
3 years ago
how much work does tension do on the laptop as it moves 2.0 mm ? express your answer with the appropriate units.
8090 [49]

The work done by tension force of 14N applied on the laptop by a rope as it moves 2.0 mm up the slope is 0.028 J

W = F d cos θ

W = Work done

F = Force

d = Displacement

θ = Angle between force and displacement vector

F = 14 N

d = 2 mm = 0.002 m

θ = 0

W = 14 * 0.002 * 1

W = 0.028 J

Work done is the change in energy of an object. So if an object moves a certain distance, work is done on the object. If the force and displacement are perpendicular to each other there is no work done on the object.

Therefore, the work done by tension on the laptop is 0.028 J

To know more about work done

brainly.com/question/12834956

#SPJ4

8 0
1 year ago
I REALLY NEED HELP
ikadub [295]
The first law of thermodynamics states the conservation of energy and heat where the total energy in an isolated system may be transformed into another, but never created or destroyed. If 286 J of energy was released to the room, then also 286 J of energy was also removed from food in that refrigerator assuming it is an isolated system.   :)

Read more on Brainly - brainly.com/sf/question/3844753
I tried to help
3 0
3 years ago
What are the magnitude and direction of electric field at the center of square?
Kobotan [32]

Answer:

hello the diagram related to this question is missing attached below is the missing diagram

Answer :

The magnitude of the electric field = 4KQ / L^2

direction = 45° east to south

Explanation:

The magnitude of the electric field = 4KQ / L^2

direction = 45° east to south

6 0
3 years ago
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