(a) 25lx
(b) 11.11lx
<u>Explanation:</u>
Illuminance is inversely proportional to the square of the distance.
So,

where, k is a constant
So,
(a)
If I = 100lx and r₂ = 2r Then,

Dividing both the equation we get

When the distance is doubled then the illumination reduces by one- fourth and becomes 25lx
(b)
If I = 100lx and r₂ = 3r Then,

Dividing equation 1 and 3 we get

When the distance is tripled then the illumination reduces by one- ninth and becomes 11.11lx
When looking at it from a physics standpoint, the thick padding decreases the amount of force that a player experiences. Force equals mass times acceleration where acceleration is distance over time. The thick padding increases the amount of time the player makes contact with the post which decreases force.
Answer
given,
distance of first satellite = 48,000 Km
distance of second satellite = 64,000 Km
orbital period = 6.39 day
Using equation of time period

now, from the above equation we can say that only variable is Time period and r is the radii of orbit.
from the first satellite




for second satellite



Answer:
1.11 dioptre
Explanation:
= Distance of the image = - (125 - 2) = - 123 cm
= Distance of the object = 54 - 2 = 52 cm
= Focal length of the lens
Using the equation


cm
Power of the lens is given as


Dioptre
The cart is moving by simple harmonic motion, and its position at time t is described by

where
A is the amplitude of the oscillation

is the angular frequency
The amplitude of the oscillation corresponds to the maximum displacement of the spring, which corresponds to the initial position where the spring was released:
A=0.250 m
The period of the motion is T=5.67 s, and the angular frequency is related to the period by

Therefore now we can calculate the position of the system at the time t=29.6 s: