True is the correct answer
<span>C. The net force is perpendicular to the motion.
When you swing a yo-yo in a circle around your head, the net force
is the tension in the string, pointing toward the center of the circle.
There's nothing there that provides any force parallel or opposite to
the motion.
When the Earth revolves around the Sun in a circular orbit, the net force
is the gravitational force between the Sun and the Earth. There's nothing
</span>there that provides any force parallel or opposite to the motion.
Answer:
Centripetal acceleration of the car is (4.96 g) m/s²
Explanation:
It is given that,
Radius of circle, r = 95 m
Speed of the car, v = 68 m/s
We need to find the centripetal acceleration. It is given by :
So,
Since, g = 9.8 m/s²
So,
So, the magnitude of the centripetal acceleration is (4.96 g) m/s². Hence, this is the required solution.
Answer:
Not Equal.
Explanation:
As the direction from New York to Miami (due South) is different from the direction from New York to Chicago (due West), the 2 velocities are not equal despite having the same magnitude. If both cars are to travel to the same destination at same speed, their velocities would be equal.
Explanation:
"Rank the magnitude of the torque the signs exert about the point at which the rod is attached to the side of the building."
Torque is the cross product of the radius vector and force vector.
τ = r × F
The magnitude of the torque is the force times the perpendicular distance. In other words, it is the force times distance times the sine of the angle between them.
τ = F r sin θ
Let's assume the length of each rod is L meters. In each case, the weight is a vertical force, so the perpendicular distance is the horizontal distance between the wall and the sign.
A) τ = (50 kg × 10 m/s²) (L sin 30° m)
τ = 250L Nm
B) τ = (100 kg × 10 m/s²) (L m)
τ = 1000L Nm
C) τ = (50 kg × 10 m/s²) (L sin 60° m)
τ ≈ 433L Nm
D) τ = (90 kg × 10 m/s²) (L m)
τ = 900L Nm
Ranked from greatest to least:
B > D > C > A