Ask question

Ask question

All categories

tensa zangetsu [6.8K]

3 years ago

5

A positive statement is:________. a. reflects oneâs opinions. b. can be shown to be correct or incorrect. c. a value judgment. d

. based upon an optimistic judgment.

1 answer:

kenny6666 [7]3 years ago

8 0

Answer:

b

Explanation:

You might be interested in

At which position is the northern hemisphere experiencing winter?

Leto [7]

The answer would be point A.

Hope this helped you.

6 0

4 years ago

On a horizontal axis whose unit is the meter, a linear load ranging from 0 to 1 ma a linear load distribution = 2 nC / m.

Dimas [21]

Answer:

The correct answer is - 8.99N/C

Explanation:

$dE=k\dfrac{dq}{x^2}\\ dq=\lambda{dx}\\ \lambda=2nC/m\\ dq=2dxnC\\ dE=k\dfrac{2dx}{x^2}\\ E=2k\int_1^2\dfrac{dx}{x^2}\\ E=2k(\frac{-1}{x})_1^2=k\times10^{-9}N/C\\ E=8.99\times10^9\times10^{-9}N/C\\ E=8.99N/C\\dE=k$

6 0

3 years ago

The magnitude of the magnetic force on a current-carrying wire held in a magnetic

Kamila [148]

Answer:

All of the above

Explanation:

The magnitude of the magnetic force on a current-carrying wire held in a magnetic is given by the equation $F = BIlsin \theta$

Where B = Strength of the magnetic field

I = The current carried by the wire

l = length of the wire in the magnetic field

θ = Angle between the wire and the magnetic field

Based on the relationship written above, the magnitude of the magnetic force on the current - carrying wire in the magnetic field depends on the strength of the magnetic field (B), length of the wire(l), current in the wire (I).

All the options are correct.

3 0

4 years ago

A ball is thrown horizontally at a speed of 24 meters per second from the top of a cliff. If the ball hits the ground 6.0 second

makkiz [27]

Answer:

144 meters

Explanation:

it takes 6 seconds to hit the ground right and the ball lays off 24 m per second .

so by the time the ball hits the ground 6 seconds passed. so that means the cliff is 6.0×24=144

4 0

3 years ago

How can you tell if the force is attractive or repulsive in electrostatics?

Anni [7]

The electrostatic force of attraction or repulsion is can be found as follows,

let us consider 2 bodies in gravitational field of earth. Let the distance between those two bodies is equal to r meters. The charge on the first body is Q1 and charge on second body is Q2.
By columbs force, <u>F </u><u /><u>α Q1×Q2</u><u>
</u> r²
F=<u>k Q1×Q2 </u> where k-gravitational constant.
<u /> r²

Ask me, if you have any doubt regarding this.

5 0

4 years ago

Read 2 more answers