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ikadub [295]
3 years ago
6

Evaluate [(30+6)-3^2] ÷ by 9·2

Mathematics
2 answers:
kow [346]3 years ago
8 0

Answer:

PEMDAS

[(30+6)-3^2] ÷ by 9·2

[(30+6)-9] ÷ by 9·2

[(36)-9] ÷ by 9·2

(27) ÷ by 9·2

Division comes first in this equation. Multiplication & Division goes from left to right when using PEMDAS. Same thing goes for Addition & Subtraction.

[(27) ÷ 9] · 2

(3) · 2

Answer: 6

Hopefully that made sense!

Step-by-step explanation:

Andrei [34K]3 years ago
6 0

_

Step-by-step explanation:

hello..................

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Help me plz can somewon help me
Dmitrij [34]

Answer:

The answer is 6x10^-4.

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the  

10 .

If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

7 0
3 years ago
Read 2 more answers
$250, 2.85, 3 years find the simple interest SHOW WORK 20 POINTS
Mazyrski [523]
Ok so what we need to find is 3 years of the simple interest so let’s get to it!

Ok so we found the principal price which is 250.00

And our rate is going to be 2.85%

A=P(1+rt)

Therefore the answer is going to be A=$271.38, therefore from the simple interest on a principal of $250.00 at a rate of 2.85% per year for 3 years is $271.38.

5 0
3 years ago
What is the equation in slope-intercept from of the line that passes through the point (3, 1) and is parallel to the line repres
Murljashka [212]
Parallel = same slope
Y = 2.4x + b
Plug in the point to find b
1 = 2.4(3) + b
1 = 7.2 + b
b = -6.2
Final equation: y = 2.4x - 6.2
3 0
2 years ago
Pleas help me it hard for me
Anon25 [30]

Answer:

Step-by-step explanation:

The area of the rectangle is 3x(2x+5)=6x^2 + 15x

The are of the triangle is 2(x-3)/2 = x-3

Now subtract the triangle are from the rectangles area

6x^2 + 15x - x + 3 = 6x^2 + 14x + 3

3 0
3 years ago
What is the maximum value of the feasible regions if P = 120x + 100y
harkovskaia [24]

Answer:

The maximum value of the feasible regions is P=500

Step-by-step explanation:

we know that

To find out the maximum value of the feasible regions, substitute the value of x and the value of y of each region in the objective function P and then compare the results

we have

P=120x+100y

Region 1 (0,5)

For x=0, y=5

substitute

P=120(0)+100(5)=500

Region 2 (0,4)

For x=0, y=4

substitute

P=120(0)+100(4)=400

Region 3 (4,0)

For x=4, y=0

substitute

P=120(4)+100(0)=480

Region 4 (3,0)

For x=3, y=0

substitute

P=120(3)+100(0)=360

Compare

The maximum value of the feasible regions is P=500

5 0
3 years ago
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