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ikadub [295]
3 years ago
6

Evaluate [(30+6)-3^2] ÷ by 9·2

Mathematics
2 answers:
kow [346]3 years ago
8 0

Answer:

PEMDAS

[(30+6)-3^2] ÷ by 9·2

[(30+6)-9] ÷ by 9·2

[(36)-9] ÷ by 9·2

(27) ÷ by 9·2

Division comes first in this equation. Multiplication & Division goes from left to right when using PEMDAS. Same thing goes for Addition & Subtraction.

[(27) ÷ 9] · 2

(3) · 2

Answer: 6

Hopefully that made sense!

Step-by-step explanation:

Andrei [34K]3 years ago
6 0

_

Step-by-step explanation:

hello..................

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Answer: 17/2

Step-by-step explanation: 2/3 of 12 3/8 = 8.25

8.25 as a fraction= 17/2.

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Is the function y= sin(x)/x even, odd or neither
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The number of responses to a survey are shown in the Pareto chart. The survey asked 1052 adults how they would grade the quality
Goryan [66]

Answer: (a) P(no A) = 0.935

              (b) P(A and B and C) = 0.0005

              (c) P(D or F) = 0.379

              (d) P(A or B) = 0.31

Step-by-step explanation: <u>Pareto</u> <u>Chart</u> demonstrates a relationship between two quantities, in a way that a relative change in one results in a change in the other.

The Pareto chart below shows the number of people and which category they qualified each public school.

(a) The probability of a person not giving an A is the difference between total probability (1) and probability of giving an A:

P(no A) = 1-\frac{68}{1052}

P(no A) = 1 - 0.065

P(no A) = 0.935

b) Probability of a grade better than D, is the product of the probabilities of an A, an B and an C:

P(A and B and C) = (\frac{68}{1052})(\frac{258}{1052})(\frac{327}{1052})

P(A and B and C) = \frac{5736888}{1164252608}

P(A and B and C) = 0.0005

c) Probability of an D or an F is the sum of probabilities of an D and of an F:

P(D or F) = \frac{269}{1052} +\frac{130}{1052}

P(D or F) = \frac{399}{1052}

P(D or F) = 0.379

d) Probability of an A or B is also the sum of probabilities of an A and of an B:

P(A or B) = \frac{68}{1052} +\frac{258}{1052}

P(A or B) = \frac{326}{1052}

P(A or B) = 0.31

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3 years ago
Suppose a random sample of n measurements is selected from a binomial population with probability of success p = .39. Given n =
Oksi-84 [34.3K]

Answer:

The answer is below

Step-by-step explanation:

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b) The mean of the distribution of sample means (also known as the Expected value of M) is equal to the population mean μ.

\mu_x=\mu=np=300*0.39=117

c) The standard deviation of the distribution of sample means is called the Standard Error of M, it is given by:

\sigma_x=\sqrt{np(1-p)} =\sqrt{300*0.39(1-0.39)} =8.44

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