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LenKa [72]
3 years ago
9

Write the expression in exponential form. log 3^9= 2

Mathematics
1 answer:
denis23 [38]3 years ago
5 0

Answer: 3^2

Step-by-step explanation:

remember logb a=n <---> a=b^n

so therefor the answer is log3 9=2 ---> 9 = 3^2

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Math questions part 2<br> pls help
ohaa [14]

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5 0
3 years ago
determine an equation and the radius for the circle that has its centre at the origin (0,0) passes through the point A 4-3
g100num [7]

Given:

The center of the circle is at (0,0).

The circle passes through the point A(4,-3).

To find:

The radius and the equation of the circle.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The radius of the circle is the distance between the points (0,0) and (4,-3).

r=\sqrt{(4-0)^2+(-3-0)^2}

r=\sqrt{(4)^2+(-3)^2}

r=\sqrt{16+9}

r=\sqrt{25}

r=5

So, the radius of the circle is 5 units.

The standard form of a circle is

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is center of circle and r is the radius.

Putting h=0, k=0, r=5, we get

(x-0)^2+(y-0)^2=5^2

x^2+y^2=25

Therefore, the radius of the circle is 5 units and the equation of the circle is x^2+y^2=25.

6 0
3 years ago
A bag contains 12 red marbles, 10 green ones, 2 yellow ones, 19 blue ones, &amp; 9 purple marbles. What is the probability of pu
Reika [66]
Add up all the amounts of marbles, which gives you 52, then see how many greens ones there are.
So the answer would be 10/52
5 0
3 years ago
Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x = t7 + 1, y = t8
Jet001 [13]
I must assume that you meant t=1 (not t=?1).  If t=1, here's what we'd do:

1.  Find the x and y values corresponding to t=1.  They are:
      x=(1)^7+1=2     and    y=(1)^8+1=2.  (Please note:  write t^8 instead of t8,                and write t^7 instead of t7.)
2.  The slope of the tangent line to the graph is
                          dy/dt            8t^7+1
          dy/dx = ----------   = ---------------- with 1 substituted for t
                         dx/dt              7t^6
  
      Thus, dy/dx (at t=1) = 9/7

3.  Now we have both a point (2,2) on the graph and the slope of the tangent line to the curve at that point:  9/7

4.  The tangent line to the curve at (2,2) is  found by using the point-slope formula:

y-y1 = m(x-x1)

which comes out to y-2 = 9/7(x-2), or 7y-14 = 9(x-2).  You could, if you wished, simplify this result further (e. g., by solving for y in terms of x).
8 0
3 years ago
2x - 5y = 4<br> 3x - 7y = 5
VMariaS [17]

Answer:

(-3,-2)

Step-by-step explanation:

2x-5y=4

3x-7y=5

solve the equation

x=2+5/2y

3x-7y=5

substitute the value of x into an equation

3(2+5/2y)-7y=5

multiply 3 to 2. and. 3 to 5/2y

6+15/2y-7y=5

minus 6 to 5 and. add 15/2y to -7y

-1/2y=1

divide both sides by -1/2

y= -2

substitute the value of -2 into an equation

x=2+5/2•(-2)

multiply 5/2 to -2

x=2+-5

add but since 5 is negative then subtract the numbers

x= -3

combine y= -2 and x= -3 as a point

So the answer is (-3,-2)

3 0
3 years ago
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