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3 years ago

5

Tina's Jack Russell weighed 19.5 pounds. This week, her dog weighed 21.8 pounds. Find the percent of change in the weight of her

dog?

1 answer:

spin [16.1K]3 years ago

8 0

Answer:

90%

Step-by-step explanation:

19.5 divided by 21.8 = 0.89449541 = 0.89% or 0.9%

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Which two of the following are not characteristics of surveys?

OLEGan [10]

Answer: A. The study compares two or more treatments (possibly including "no treatment").

C. The study involves one or more treatment groups and a control group.

Step-by-step explanation:

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3 years ago

IF PASSPORT is written as RCUURQTV, then how will BOOKLET be coded?

TiliK225 [7]

Answer: DQQMNGV

Step-by-step explanation: Each letter is shifted two letters to the right on a letter strip (a -> b -> c), so BOOKLET would be DQQMNGV.

Hope this helps!

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3 years ago

This system has one solution what is the y cordinate of the solution

Lerok [7]

Answer:

y = 10

Step-by-step explanation:

Given the 2 equations

y = - 2x + 4 → (1)

y = x² + 4x + 13 → (2)

Since both equations express y in terms of x we can equate them

x² + 4x + 3 = - 2x + 4 ( subtract - 2x + 4 from both sides )

x² + 6x + 9 = 0 ← in standard form

(x + 3)² = 0 ← in factored form

x + 3 = 0 ⇒ x = - 3 with multiplicity 2

Substitute x = - 3 into (1)

y = 6 + 4 = 10

6 0

3 years ago

A distributor ships DVDs to several stores. The shipping boxes contain several DVDs (in their cases) plus a layer of padding at

Snowcat [4.5K]

Answer:

Option B.

Step-by-step explanation:

It is given that,

Thickness of Each DVD case = 14 mm

Thickness of each layer of padding = 10 mm

Length of the interior of the box = 132 mm

Let d represents the number of DVDs that the distributor can fit into one box with two layers of padding.

Thickness of d DVD cases = 14d mm

Thickness of two layers of padding = 10×2=20 mm

Total thickness of d DVD cases and 2 layers of padding = 14d+20

Total thickness must be less than or equal to 132.

$14d+20\leq 132$

Therefore, the correct option is B.

7 0

3 years ago

Solve the problem. If at a given speed a car can travel 95.6 miles on 4 gallons of gasoline, how far can the car can travel on 6

VMariaS [17]

Answer: The correct option is (B) 1625.2 miles.

Step-by-step explanation: Given that at a given speed a car can travel 95.6 miles on 4 gallons of gasoline.

We are to find the distance that the car can travel on 68 gallons at the same speed.

We will be using the UNITARY method to solve the given problem.

Distance traveled by the car on 4 gallons of gasoline = 95.6 miles.

So, the distance traveled by the car on 1 gallon of gasoline will be

$\dfrac{95.6}{4}=23.9~\textup{miles}.$

Therefore, the distance traveled by the car in 68 gallons of gasoline is given by

$23.9\times68=1625.2~\textup{miles}.$

Thus, the required distance traveled by the car on 68 gallons of gasoline is 1625.2 miles.

Option (B) is CORRECT.

3 0

3 years ago