Answer:
D, 22x^9
Step-by-step explanation:
Here's a key for end behavior: Look at the leading term
x^even = x -> neg inf, f(x) -> pos inf; x -> pos inf, f(x) -> pos inf
-x^even = x -> neg inf, f(x) -> neg inf; x -> pos inf, f(x) -> neg inf
x^odd = x -> neg inf, f(x) -> neg inf; x -> pos inf, f(x) -> pos inf
-x^odd = x -> neg inf, f(x) -> pos inf; x -> pos inf, f(x) -> neg inf
Since, a regular hexagon has an area of 750.8 square cm and The side length is 17 cm.
We have to find the apothem of the regular hexagon.
The formula for determining the apothem of regular hexagon is 
, where 's' is any side length of regular hexagon and 'n' is the number of sides of regular hexagon.
So, apothem = 
= 
= 
= 14.78 units
Therefore, the measure of apothem of the regular hexagon is 14.7 units.
Option B is the correct answer.
Answer:
BD = 3 units
Step-by-step explanation:
Since, AD is an angle bisector of ∠BAC,
m∠BAD = m∠CAD = 20°
CD = 3 units
In ΔACD and ΔABD,
m∠BAD = m∠CAD = 20° (Given)
AD ≅ AD [Reflexive property]
Therefore, by H-A property of congruence both the triangles will be congruent.
And by CPCTC,
CD ≅ BD = 3 units
The number you are looking for is 995
