Verbal Communication. Verbal communication occurs when we engage in speaking with others. ...
Non-Verbal Communication. What we do while we speak often says more than the actual words. ...
Answer:
Following code will store the largest value in array parkingTickets in the variable mostTickets
mostTickets = parkingTickets[0];
for(int k = 0; k<parkingTickets.length; k++)
{
if(parkingTickets[i]>mostTickets)
{
mostTickets = parkingTickets[i];
}
}
Explanation:
In the above code segment, initially the number of tickets at first index is assumed as largest value of tickets in array.
Then using a for loop each value in the array parkingTickets is compared with the current mostTickets value.
If the compared value in parkingTickets array is larger than the current mostTickets value. Then that value is assigned to mostTickets.
This process is repeated for all elements in array.
Thus after looping through each element of array the largest value in array will get stored in mostTickets variable.
Commands into software documents tools
Answer:
The number of subproblems are given as 
while the value of T(n) to be less than S(n) is for 342.
Explanation:
The number of subproblems are given as
Asymptotic running time for Strassen’s algorithm is 
Now, when a increases, number of subproblems determines the asymptotic running time of the problem and case 1 of master theorem applies. So, in worst case, asymptotic running time of the algorithm will be
Now, for T(n) to be smaller than S(n)
So,
So,
a=342
