Answer:
Step-by-step explanation:
Given
The attached graph
Required
This is the point where
On the attached graph;
when
Hence:
Answer:
i need points rq thanks so much
Step-by-step explanation:
imma go waste these points now
Answer:
t =12 m
Step-by-step explanation:
We can use similar triangles and proportions to solve this problem.
Put the smaller triangle on top and the larger triangle on bottom
12 9
------ = -------
16 t
Solve by using cross products
12 t = 9*16
12 t =144
Divide by 12
12t/12 = 144/12
t = 12
Answer:
Binomial; \mu p=87.5, \sigma p=7.542
Step-by-step explanation:
- a distribution is said be a binomial distribution iff
- The probability of success of that event( let it be p) is same for every trial
- each trial should have 2 outcome : p or (1-p) i.e, success or failure only.
- there are fixed number of trials (n)
- the trials are independent
- here, the trials are obviously independent ( because, one person's debt doesn't influence the other person's)
- the probability of success(0.35) is same for every trial
(35/100=0.35 is the required p here)
[since, the formula for 
]
[since, the formula for [tex]\sigma _{p} =\sqrt{n*(p)*(1-p)}
- therefore, it is Binomial; \mu p=87.5, \sigma p=7.542
9514 1404 393
Answer:
x ≠ 3
Step-by-step explanation:
In any case, the domain is restricted to values of the variable for which the function is defined. The value 1/0 is not defined, so the variable cannot allow the denominator to be zero. The denominator x-3 will be zero for x=3, so that value of the variable cannot be in the domain.
The domain is all real numbers except x=3.
_____
<em>Additional comments</em>
It is useful to become familiar with the domains of different functions. As we saw above, the reciprocal of 0 is undefined. The square root of a negative number is undefined. The log of a non-positive number is undefined. Trig functions are defined everywhere, but their inverse functions are not. Polynomial functions are defined everywhere, but ratios of polynomials have the same restriction on denominators that we see above.
