X+y=16
the sum of the squares is
x^2+y^2=sum
solve for y in first equation
x+y=16
y=16-x
subsitiute that for y in other equation
x^2+(16-x)^2=sum
x^2+x^2-32x+256=sum
2x^2-32x+256=sum
take derivitive to find the minimum value (or just find the vertex because the parabola opens up)
derivitive is
4x-32=derivitve of sum
the max/min is where the derivitive equals 0
4x-32=0
4x=32
x=8
at x=8
so then y=16-8=8
the smallest value then is 8^2+8^2=64+64=128
rewrite the fractions so the have the same denominator ( bottom number)
Multiply 2/5 by 2 to get 4/10
Now you can add 4/10 and 3/10 to make 7/10.
7/10 of the land is corn or wheat.
Answer:
first of all its not d since the y intercept is negitive
then its not b since its sloping down
so the slop is either 7/5 or 5/7
since rise/run it has to be 7/5
Hope This Helps!!!
I'm not to sure but i'm pretty sure the substitution method is the way to solve this
Your answer would be 58/75 or in decimal <span>0.77333333333
Hope that helps!
~Take care!~ :-3</span>
