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ohaa [14]
2 years ago
9

Compare 3/4 and 9/11

Mathematics
2 answers:
weeeeeb [17]2 years ago
8 0
To solve this simply divide 4 by 3 and use the long division and do the same for 11 and 9, then compare the values.
QveST [7]2 years ago
4 0

Holaaa!

To compare 3/4 and 9/11 we must first make the denominators the same number. To do this, we can multiply the numerators and denominators of the numbers by eachother. See below.

Denominators - 4 and 11 - we are going to multiply these to find out what the denominator of both our fractions will be.

4 * 11 = 44 - the denominator is therefore, 44.

Now we need to multiply the numerators by the opposite denominators. Numerators - 3 and 9 - (multiply by the opposite denominators) - 3 * 11 = 33 (33/44) - 9 * 4 = 36 (36/44)

Now that we've done that, we can compare our fractions.

9/11 = 36/44  ?  3/4 = 33/44

Which is greater? The answer is 9/11 (36/44)

9/11 > 3/4  

I truly hope this helps you!

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∆ABC is similar to ∆DEF. The ratio of the perimeter of ∆ABC to the perimeter of ∆DEF is 1 : 10. The longest side of ∆DEF measure
exis [7]

Answer:

Part 1) The length of the longest side of ∆ABC  is 4 units

Part 2) The ratio of the area of ∆ABC to the area of ∆DEF is \frac{1}{100}

Step-by-step explanation:

Part 1) Find the length of the longest side of ∆ABC

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

The ratio of its perimeters is equal to the scale factor

Let

z ----> the scale factor

x ----> the length of the longest side of ∆ABC

y ----> the length of the longest side of ∆DEF

so

z=\frac{x}{y}

we have

z=\frac{1}{10}

y=40\ units

substitute

\frac{1}{10}=\frac{x}{40}

solve for x

x=(40)\frac{1}{10}

x=4\ units

therefore

The length of the longest side of ∆ABC  is 4 units

Part 2) Find the ratio of the area of ∆ABC to the area of ∆DEF

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of ∆ABC

y ----> the area of ∆DEF

z^{2}=\frac{x}{y}

we have

z=\frac{1}{10}

so

z^2=(\frac{1}{10})^2

z^2=\frac{1}{100}

therefore

The ratio of the area of ∆ABC to the area of ∆DEF is \frac{1}{100}

3 0
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Answer:6

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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SO, if a quadratic equation has 4-i as a solution, the other solution must be 4+i.

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Step-by-step explanation:

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