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ohaa [14]
2 years ago
9

Compare 3/4 and 9/11

Mathematics
2 answers:
weeeeeb [17]2 years ago
8 0
To solve this simply divide 4 by 3 and use the long division and do the same for 11 and 9, then compare the values.
QveST [7]2 years ago
4 0

Holaaa!

To compare 3/4 and 9/11 we must first make the denominators the same number. To do this, we can multiply the numerators and denominators of the numbers by eachother. See below.

Denominators - 4 and 11 - we are going to multiply these to find out what the denominator of both our fractions will be.

4 * 11 = 44 - the denominator is therefore, 44.

Now we need to multiply the numerators by the opposite denominators. Numerators - 3 and 9 - (multiply by the opposite denominators) - 3 * 11 = 33 (33/44) - 9 * 4 = 36 (36/44)

Now that we've done that, we can compare our fractions.

9/11 = 36/44  ?  3/4 = 33/44

Which is greater? The answer is 9/11 (36/44)

9/11 > 3/4  

I truly hope this helps you!

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Answer:

P(t) = 100e^{0.0251t}

The doubling time is of 27.65 minutes.

Step-by-step explanation:

Exponential equation of growth:

The exponential equation for population growth is given by:

P(t) = P(0)e^{kt}

In which P(0) is the initial value and k is the growth rate.

A freshly inoculated bacterial culture of Streptococcus contains 100 cells.

This means that P(0) = 100. So

P(t) = 100e^{kt}

When the culture is checked 60 minutes later, it is determined that there are 450 cells present.

This means that P(60) = 450, and we use this to find k. So

450 = 100e^{60k}

e^{60k} = 4.5

\ln{e^{60k}} = \ln{4.5}

60k = \ln{4.5}

k = \frac{\ln{4.5}}{60}

k = 0.0251

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P(t) = 100e^{0.0251t}

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This is t for which P(t) = 2P(0) = 200. So

200 = 100e^{0.0251t}

e^{0.0251t} = 2

\ln{e^{0.0251t}} = \ln{2}

0.0251t = \ln{2}

t = \frac{\ln{2}}{0.0251}

t = 27.65

The doubling time is of 27.65 minutes.

7 0
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Answer:

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Step-by-step explanation:

i hope it will help you

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Step-by-step explanation:

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