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2 years ago

7

Anyone know this and can help?!

1 answer:

DENIUS [597]2 years ago

7 0

Answer:

65.4°

Step-by-step explanation:

According to question

The equation is

Cos(x)=5/12

x=acos(5/12)

x=65.4°

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Pleaseeeee help with 7-12 I’m strugglingggg!!!

bearhunter [10]

Answer:

7-12 is 5

Step-by-step explanation:

First you want to turn this into addition and make 12 it's inverse 7+(-12) now with 7+(-12) it is basically 12-7. 12-7=5 so your answer is 5

5 0

3 years ago

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15 = -4p + 7<br><br><br> solving equation

Ratling [72]

Answer:

p = -2

Step-by-step explanation:

15 = -4p + 7

4p + 15 = 7

4p + 15 - 15 = 7 - 15

4p = -8

4p/4 = -8/4

p = -2

8 0

3 years ago

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Use Lagrange multipliers to find the maximum and minimum values of (i) f(x,y)-81x^2+y^2 subject to the constraint 4x^2+y^2=9. (i

sp2606 [1]

i. The Lagrangian is

$L(x,y,\lambda)=81x^2+y^2+\lambda(4x^2+y^2-9)$

with critical points whenever

$L_x=162x+8\lambda x=0\implies2x(81+4\lambda)=0\implies x=0\text{ or }\lambda=-\dfrac{81}4$

$L_y=2y+2\lambda y=0\implies2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_\lambda=4x^2+y^2-9=0$

If $x=0$ , then $L_\lambda=0\implies y=\pm3$ .
If $y=0$ , then $L_\lambda=0\implies x=\pm\dfrac32$ .
Either value of $\lambda$ found above requires that either $x=0$ or $y=0$ , so we get the same critical points as in the previous two cases.

We have $f(0,-3)=9$ , $f(0,3)=9$ , $f\left(-\dfrac32,0\right)=\dfrac{729}4=182.25$ , and $f\left(\dfrac32,0\right)=\dfrac{729}4$ , so $f$ has a minimum value of 9 and a maximum value of 182.25.

ii. The Lagrangian is

$L(x,y,z,\lambda)=y^2-10z+\lambda(x^2+y^2+z^2-36)$

with critical points whenever

$L_x=2\lambda x=0\implies x=0$ (because we assume $\lambda\neq0$ )

$L_y=2y+2\lambda y=0\implies 2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_z=-10+2\lambda z=0\implies z=\dfrac5\lambda$

$L_\lambda=x^2+y^2+z^2-36=0$

If $x=y=0$ , then $L_\lambda=0\implies z=\pm6$ .
If $\lambda=-1$ , then $z=-5$ , and with $x=0$ we have $L_\lambda=0\implies y=\pm\sqrt{11}$ .

We have $f(0,0,-6)=60$ , $f(0,0,6)=-60$ , $f(0,-\sqrt{11},-5)=61$ , and $f(0,\sqrt{11},-5)=61$ . So $f$ has a maximum value of 61 and a minimum value of -60.

5 0

2 years ago

Fill in the missing number.<br> 6 x 4 =(<br> x 4) + (3 x 4)

amid [387]

Answer:

6x4= 24

x4)+(3x4)=12

bsnskzifkznsnaksifi

7 0

2 years ago

Helpppppppppppppppp meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Licemer1 [7]

Answer:

a) = 4.198

b) = 4.146

Step-by-step explanation:

a) 15.444/6+0.232*7

do pemdas

=15.444/6+(0.232*7)

=(15.444/6)+1.624

=2.574+1.624

a) = 4.198

b) (1.709+0.364)*6/3

pemdas again

=(2.073) *6 / 3

=12.438 / 3

b) =4.146

Hope this helps :)

8 0

2 years ago

Read 2 more answers