3. Suppose U= {1,2,3,4,5,6,7,8,9,10} is the universal set and Q= {3,6,9}. What is Q'?
Readme [11.4K]
Answer:
3. Q' = {1 , 2 , 4 , 5 , 7 , 8 , 10} ⇒ answer C
4. A ⊂ B is False ⇒ answer B
Step-by-step explanation:
3.
- The universal set U = {1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10}
- The set Q = {3 , 6 , 9}
- We need to find the complement of set Q (Q')
- The complement set of Q is the set of all elements belongs to the
universal set U but does not belong to the set Q
- That means take off all the elements belongs to set Q from the
universal set U
∵ U = {1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10}
∵ Q = {3 , 6 , 9}
- Cancel from set U the elements 3 , 6 , 9
∴ Q' = {1 , 2 , 4 , 5 , 7 , 8 , 10}
4.
- The universal set U = {1 , 2 , 3 , 4 , 5 , 6 , 7 , 8}
- The set A= {1 , 3 , 5 , 7}
- The set B= {4 , 5 , 6}
- A ⊂ B means every element in set A belongs to set B
∵ A= {1 , 3 , 5 , 7}
∵ B= {4 , 5 , 6}
∵ The elements in set A ∉ in set B
∴ A ⊂ B is False
Answer:
8.5
Step-by-step explanation:
4 + (6)(6)/8=
17/2 = 8.5
Answer:
x = 8
Step-by-step explanation:
6x - 3 = 5x + 5
Move variable to the left hand side and change their sign.
Calculate like terms.
Move constant to the right hand side and change their sign.
<u>Check our answer :-</u>
6x -3 = 5x + 5
plug the 8 as x.
- 6 ( 8 ) - 3 = 5 ( 8 ) + 5
- 48 - 3 = 40 + 5
- 45 = 45
LHS = RHS
Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
