Answer:
The domain for x is all real numbers greater than zero and less than 5 com
Step-by-step explanation:
<em><u>The question is</u></em>
What is the volume of the open top box as a function of the side length x in cm of the square cutouts?
see the attached figure to better understand the problem
Let
x -----> the side length in cm of the square cutouts
we know that
The volume of the open top box is
we have
substitute
Find the domain for x
we know that
so
The domain is the interval (0,5)
The domain is all real numbers greater than zero and less than 5 cm
therefore
The volume of the open top box as a function of the side length x in cm of the square cutouts is
Answer:
Option (2).
Step-by-step explanation:
It is given in the question,
ΔLMN is a right triangle with base LM = 3a units
Hypotenuse MN = 5a
By applying Pythagoras theorem in ΔLMN,
MN² = LM² + NM²
(5a)² = (3a)² + MN²
25a² - 9a² = MN²
MN = √16a²
MN = 4a
Therefore, vertices of the triangle will be L(0, 0), M(3a, 0) and N(0, 4a).
Option (2) will be the answer.
Answer:
40
Step-by-step explanation:
look at the picure for step by step explanation
Which of the following lists has a mode of 213? / 111, 108, 213, 198, 205/ /212, 215, 213, 211, 220/ /213, 278, 108, 213, 157/ /
Fed [463]
The mode is the most frequent one
The answer is 213, 278 , 108, 213, 157
2x + 4y + 2 = 3y + 5
2x + 4y - 3y + 2 - 5 = 0
2x + y - 3 = 0
