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Dmitry_Shevchenko [17]
2 years ago
12

A container has the dimensions of 10cm x 80mm x 0.15m. The density of

Chemistry
1 answer:
vesna_86 [32]2 years ago
8 0

Answer:

2.52kg

Explanation:

80mm = 8 cm

0.15m = 15 cm

volume of the container = 10m × 8cm × 15cm

= 1200 cubic centimetres

mass = density × volume

= 2.1 × 1200

= 2520g

2520/ 1000

= 2.52kilograms

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A 700.0 mL gas sample at STP is compressed to a volume of 200.0 mL, and the temperature is increased to 30.0°C. What is the new
dolphi86 [110]

Answer: The new pressure of the gas in Pa is 388462

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas at STP = 10^5Pa

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 700.0 ml

V_2 = final volume of gas = 200.0 ml

T_1 = initial temperature of gas = 273 K

T_2 = final temperature of gas = 30^oC=273+30=303K

Now put all the given values in the above equation, we get:

\frac{10^5\times 700.0ml}{273K}=\frac{P_2\times 200.0ml}{303K}

P_2=388462Pa

The new pressure of the gas in Pa is 388462

6 0
3 years ago
The picture below shows a warm air mass caught between two cooler air masses. What is this type of front called? Plz, I really n
pentagon [3]

An occluded front forms when a warm air mass is caught between two cooler air masses.

6 0
3 years ago
A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68mg of the compound yields 16.01 mg CO2 and 4.37 mg H2O
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<span>Molecular formulas tell you how many atoms of each element are in a compound, and empirical formulastell you the simplest or most reduced ratio of elements in a compound. ... Also, many compounds with different molecular formula have the same<span>empirical formula</span></span>
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3 years ago
What do you mean by antibodies​
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8 0
2 years ago
1. A gas expands and does p-v work on the surroundings equal to
azamat

The change in energy of the system : -63 J

<h3>Further explanation</h3>

Given

279 J work

216 J heat

Required

The change in energy

Solution

Laws of thermodynamics 1

ΔU=Q+W

Rules :

  • receives heat, Q +  
  • releases heat, Q -  
  • work is done by a system, W -  
  • work is done on a system, W +  

a gas work on the surrounding : W =-279 J

a gas absorb heat from surrounding : Q = +216 J

Internal energy :

= -279+216

= -63 J

3 0
2 years ago
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