Answer: 1.41725 X 10^{24} atoms
Explanation:
One male of any gas containing no. of atoms
2.5 moles of gas containing no. of atoms
The given gas is triatomic gas. Hence
No. of atoms

Answer:
The answer to your question is a) N₂ b) 3.04 g of NH₃
Explanation:
Data
mass of H₂ = 2.5 g
mass of N₂ = 2.5 g
molar mass H₂ = 2.02 g
molar mass of N₂ = 28.02 g
molar mass of NH₃ = 17.04 g
Balanced chemical reaction
3H₂ + 1 N₂ ⇒ 2NH₃
A)
Calculate the theoretical yield 3H₂ / N₂ = 3(2.02) / 28.02 = 0.22
Calculate the experimental yield H₂/N₂ = 2.5/2.5 = 1
Conclusion
The limiting reactant is N₂ (nitrogen) because the experimental proportion was higher than the theoretical proportion.
B)
28.02 g of N₂ -------------------- (2 x 17.04) g of NH₃
2.5 g of N₂ -------------------- x
x = (2.5 x 2 x 17.04) / 28.02
x = 85.2 / 28.02
x = 3.04 g of NH₃
Plants :)
Hope this helps!
Answer:
6.
2AI2O3 + heat -> 4AI + 3O2
Reaction type: Combustion
7.
2AI+ 6HCl -> 3H2 + 2AlCl3
Reaction type: Single Replacement
8.
IDK
Reaction type: Double Replacement?
Explanation:
When you doing a titration, you need to use an indicator to confirm whether the reaction is completed. When the indicator has the color change and will not change back in one minute, the reaction is finished and you don't need to add more.