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2 years ago

What does Le Châtelier's principle say about upsetting a system at

Chemistry

2 answers:

juin [17]2 years ago

8 0

Answer:

Explanation:

A system whose equilibrium has been upset will shift to restore

equilibrium.

sveta [45]2 years ago

6 0

Answer:

D. A system will not be able to restore equilibrium if conditions are

changed.

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Th e molar absorption coeffi cient of a substance dissolved in water is known to be 855 dm3 mol−1 cm−1 at 270 nm. To determine t

Olegator [25]

Answer : The percentage reduction in intensity is 79.80 %

Explanation :

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

$A=\log \frac{I_o}{I}$

$\log \frac{I_o}{I}=\epsilon \times C\times l$

where,

A = absorbance of solution

C = concentration of solution = $3.25mmol.dm^{3-}=3.25\times 10^{-3}mol.dm^{-3}$

l = path length = 2.5 mm = 0.25 cm

$I_o$ = incident light

$I$ = transmitted light

$\epsilon$ = molar absorptivity coefficient = $855dm^3mol^{-1}cm^{-1}$

Now put all the given values in the above formula, we get:

$\log \frac{I_o}{I}=(855dm^3mol^{-1}cm^{-1})\times (3.25\times 10^{-3}mol.dm^{-3})\times (0.25cm)$

$\log \frac{I_o}{I}=0.6947$

$\frac{I_o}{I}=10^{0.6947}=4.951$

If we consider $I_o$ = 100

then, $I=\frac{100}{4.951}=20.198$

Here 'I' intensity of transmitted light = 20.198

Thus, the intensity of absorbed light $I_A$ = 100 - 20.198 = 79.80

Now we have to calculate the percentage reduction in intensity.

$\% \text{reduction in intensity}=\frac{I_A}{I_o}\times 100$

$\% \text{reduction in intensity}=\frac{79.80}{100}\times 100=79.80\%$

Therefore, the percentage reduction in intensity is 79.80 %

3 0

3 years ago

4. If the DNA nitrogen bases were TACCGGAT, how would the other half of

Elena L [17]

Answer:

ATGGCCTA

Explanation:

For this we have to keep in mind that we have a specific relationship between the nitrogen bases:

-) When we have a T (thymine) we will have a bond with A (adenine) and viceversa.

-) When we have C (Cytosine) we will have a bond with G (Guanine) and viceversa.

Therefore if we have: TACCGGAT. We have to put the corresponding nitrogen base, so:

TACCGGAT

ATGGCCTA

I hope it helps!

6 0

3 years ago

An 18.0 g piece of an unidentified metal was heated from 21.5 °C to 89.0 °C. If 789.75 J of heat energy was absorbed by the meta

nydimaria [60]

Answer: The metal is Calcium.

Explanation:

To calculate the specific heat of substance during the reaction.

$q=m\times c\times \Delta T$

where,

q = heat absorbed = 789.75 J

c = specific heat of metal = ?

m = mass of substance = 18.0 g

$\Delta T_f$ = final temperature - initial temperature = $(89.0-21.5)^0C=67.5^0C$

Now put all the given values in the above formula, we get:

$789.75J=18.0g\times c\times 67.5^0C$

$c=0.65J/g^0C$

As specific heat is characteristic of each metal and thus the metal is calcium which has specific heat of $0.65J/g^0C$

5 0

2 years ago

Simplify this expression 1-c+4c-29

aliya0001 [1]

Answer:

1-c+4c+c=-28+3c

Explanation:

since,the expression can be solved,solve it and gain your answer.Don't truly trust me though.

4 0

3 years ago

Ammonia (NH3) ionizes according to the following reaction: NH3(aq) + H2O(l) ⇌ NH4+(aq) + OH–(aq) The base dissociation constant

Ira Lisetskai [31]

Answer:

pH = 9.6

Explanation:

According to Brönsted-Lowry theory, NH₃ is a base and NH₄⁺ its conjugate acid. When they are together in a solution, the form a buffer, which is used to resist abrupt changes in pH when an acid or a base is added. pOH fro a buffer can be found using Henderson-Hasselbalch equation.

$pOH = pKb + log\frac{conjugateacid}{base}$

Since NH₄Cl is a strong electrolyte, [NH₄Cl] = [NH₄⁺]

$pOH = pKb + log\frac{[NH_{4}^{+} ]}{[NH_{3}]} =4.7+log\frac{0.035M}{0.070M} =4.4$

Now, we can find pH using the following expression:

pH + pOH = 14

pH = 14 - pOH = 14 - 4.4 = 9.6

7 0

3 years ago