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igor_vitrenko [27]
3 years ago
8

One of the following sequences is arithmetic and one is geometric. Identify which one is which, and write an explicit formula fo

r each. Sequence #1: 4, 20, 100, 500. What is the explicit formula?
Mathematics
1 answer:
Svetlanka [38]3 years ago
8 0

Answer: an = 4 × 5^(n - 1)

Step-by-step explanation:

The given sequence is a geometric sequence because consecutive terms differ by a common ratio. The

formula for determining the nth term of a geometric progression is expressed as

an = a1r^(n - 1)

Where

a1 represents the first term of the sequence.

r represents the common ratio.

n represents the number of terms.

From the information given,

a1 = 4

r = 20/4 = 100/20 = 5

Therefore, the explicit formula for the sequence is

an = 4 × 5^(n - 1)

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Solve the equation 6w2 – 7w – 20 = 0.
azamat

For this case we have the following quadratic equation:

6w ^ 2-7w-20 = 0

Where:

a = 6\\b = -7\\c = -20

Its roots will be given by:

w = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\w = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (6) (- 20)}} {2 (6)}\\w = \frac {7 \pm \sqrt {49 + 480}} {12}\\w = \frac {7 \pm \sqrt {529}} {12}\\w = \frac {7 \pm23} {12}

The roots are:

w_ {1} = \frac {7 + 23} {12} = \frac {30} {12} = \frac {15} {6} = \frac {5} {2}\\w_ {2} = \frac {7-23} {12} = \frac {-16} {12} = - \frac {8} {6} = - \frac {4} {3}

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7 0
3 years ago
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Twelve percent of U.S. residents are in their forties. Consider a group of nine U.S. residents selected at random. Find the prob
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Answer:

The probability is 28 % ( approx )

Step-by-step explanation:

Since, there are only two possible outcomes in every trails ( residents are in their forties or not ),

So, this is a binomial distribution,

Binomial distribution formula,

Probability of success in x trials,

P(x)=^nC_x p^x q^{n-x}

Where, ^nC_x=\frac{n!}{x!(n-x)!}

p and q are probability of success and failure respectively and n is the total number of trials.

Let X be the event of resident who are in his or her forties.

Here, p = 12% = 0.12,

⇒ q = 1 - p = 1 - 0.12 = 0.88,

n = 9,

Hence, the probability that two or three of the people in the group are in their forties = P(X=2) + P(X=3)

^9C_2 (0.12)^2 (0.88)^{9-2}+^9C_3 (0.12)^3 (0.88)^{9-3}

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7 0
3 years ago
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