The anwser is a&c they go forward and up
SinA= 16/20= 4/5=0.8 degree
cosA=12/20=3/5=0.6 degree
tanA=16/12= 4/3=1.33 degree
Find the exact value using trigonometric identities
840, 79
Answer:
b=-0.0019a + 215
at 2500 ft, b=210.25 degrees F
Step-by-step explanation:
First find the slope. a=altitude, b = temperature
slope is b2-b1 / a2-a1
points are (8200, 199.42) and (4700, 206.07)
(206.07 - 199.42) / (4700-8200)
= 6.65/ -3500
= - 0.0019
we have b = -0.0019a + intercept
plug in a point to find intercept
199.42 = -0.0019*8200 + intercept
intercept = 199.42 + 15.58 = 215
b=-0.0019a + 215
at a=2500 ft, substitute into equation
b= -0.0019*2500 + 215
= -4.75 + 215
= 210.25 degrees F
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Answer:
8 weekend hours can now be purchased.
<em>Note: The prior information required is:</em>
<em>You purchase 26 "parking hours" that you can use over the next month to park your food truck at the fair. Weekday hours cost $2/hour and weekend hours cost $10/hour.</em>
Step-by-step explanation:
Initial cost of weekday hours = $2/ hour
Since the cost of the weekday hours is tripled, new cost = $2/ hour × 3 = $6/ hour
Total week hours purchased = 26 hours
Let the number of weekend hours be x; number of weekday hours will be 26 - x
Since the budget remains the same, therefore, the total cost of weekday parking hours and weekend parking hours will be equal to $220as expressed below;
(26 - x) × $6 + $10 × x = $220
$10x - $6x + $156 = $220
$4x = $(220 -156)
x = 64/4
x = 8 hours
Therefore, 8 weekend hours can now be purchased
