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ArbitrLikvidat [17]
3 years ago
7

Susan and her friend found a piece of metal which they want to

Chemistry
1 answer:
joja [24]3 years ago
4 0

Answer:

The given  metal is beryllium.

Explanation:

Given data:

Mass of metal = 74 g

Volume of metal = 40 cm³

Which metal is this = ?

Solution:

First of all we will calculate the density.

it is mass divided by volume.

d = m/v

d = 74 g/40 cm³

d = 1.85 g/cm³

In literature it is given that the density of beryllium is 1.85 g/cm³. Thus given  metal is beryllium.

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How many moles of oxygen are needed to react with 87 grams of aluminum
labwork [276]

Answer:

2.4 moles of oxygen are needed to react with 87 g of aluminium.

Explanation:

Chemical equation:

4Al(s)  + 3O₂(l)   → 2AlO₃(s)

Given data:

Mass of aluminium = 87 g

Moles of oxygen needed = ?

Solution:

Moles of aluminium:

Number of moles of aluminium= Mass/ molar mass

Number of moles of aluminium= 87 g/ 27 g/mol

Number of moles of aluminium= 3.2 mol

Now we will compare the moles of aluminium with oxygen.

                              Al         :         O₂

                               4          :         3

                               3.2       :         3/4×3.2 = 2.4 mol

2.4 moles of oxygen are needed to react with 87 g of aluminium.

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2 years ago
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How many molecules of glucose are produced by each cycle of the light reaction?
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Answer:

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