Answer:
The empirical formula is SF6 (option E)
Explanation:
Step 1: Data given
Mass of sulfur = 3.21 grams
Mass of fluorine = 11.4 grams
Molar mass sulfur = 32.065 g/mol
Molar mass fluorine = 19.00 g/mol
Step 2: Calculate moles
Moles = mass /molar mass
Moles sulfur = 3.21 grams / 32.065 g/mol
Moles sulfur = 0.100 moles
Moles fluorine = 11.4 grams / 19.00 g/mol
Moles fluorine = 0.600 moles
Step 3: Calculate mol ratio
We divide by the smallest amount of moles
S: 0.100 / 0.100 = 1
F : 0.600 / 0.100 = 6
The empirical formula is SF6 (option E)
An ionization suppressor is an alkali metal capable of preventing ionization, which can be used in atomic spectroscopy to determine matter composition.
<h3>What is ionization?</h3>
Ionization refers to the phenomena capable of converting neutral atoms/molecules to electrically charged atoms/ions.
Ionization is a process by which radiation (e.g., alpha, beta, gamma rays) can pass energy to inert matter.
Some examples of ionization suppressors include salts of alkali metals (for example, potassium), which can be used in atomic spectroscopy to determine matter composition.
Learn more about ionization here:
brainly.com/question/1445179
Answer:
The answer is indeed true
Explanation:
Answer:
40/220 ×100=18.6 is all I got I know that by heart so um yea
Explanation:
