All categories

3 years ago

Which of the following is an example of a solution?

Chemistry

1 answer:

Elenna [48]3 years ago

8 0

Answer:

A: an iron alloy.

Explanation:

Because iron alloy consists of minor components that are distributed within the major component, which is the basic requirement for a solution.

You might be interested in

Name the SI base units that are important in chemistry, and give the SI units for expressing the following: (a)length, (b) volum

kirza4 [7]

Answer and Explanation:

The basic unit which are that are important in chemistry are meter, kilogram ,mol, $m^3$

Candela which is the unit of luminous of intensity is not so important in physics

(a) SI unit of length is meter (m)

(b) Si unit of volume is $m^3$

(d) SI unit of time is second (s)

(e) SI unit of temperature is kelvin (K)

4 0

3 years ago

A mixture of helium and hydrogen gases, at a total pressure of 751 mm Hg, contains 0.447 grams of helium and 0.193 grams of hydr

Margaret [11]

Answer:

D0wnload Phot0Math........................

Explanation:

4 0

3 years ago

Which of the following would be found in both eukaryotic AND prokaryotic cells?

beks73 [17]

Nucleus ,endoplasmic reticulum

7 0

3 years ago

Read 2 more answers

To interconvert the concentration units molality (m) and mass percent, you must also know the density of the solution. A) True B

uranmaximum [27]

Answer:

The correct answer is option false.

Explanation:

Molality of the solution defined as moles of substance present in 1 kilogram of solvent.

Moles = $\frac{Mass of solute}}{\text{molar mass of solute}}$

$Molality=\frac{Moles}{\text{Mass of solvent(kg)}}$

Mass of percent (w/w%) of the solution is defined as amount of solute present in 100 grams of solution.

$(w/w\%)_=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100$

So, if want to inter-convert molality into mass percent we can do that without knowing density of solution.

Mass of solution = Mass of solute + Mass of solvent

7 0

3 years ago

For a particular reaction at 235.8 °C, ΔG=−936.92 kJ/mol , and ΔS=513.79 J/(mol⋅K) . Calculate ΔG for this reaction at −9.9 °C.

Rudik [331]

Answer:

-138.9 kJ/mol

Explanation:

Step 1: Convert 235.8°C to the Kelvin scale

We will use the following expression.

K = °C + 273.15 = 235.8°C + 273.15 = 509.0 K

Step 2: Calculate the standard enthalpy of reaction (ΔH°)

We will use the following expression.

ΔG° = ΔH° - T.ΔS°

ΔH° = ΔG° / T.ΔS°

ΔH° = (-936.92kJ/mol) / 509.0K × 0.51379 kJ/mol.K

ΔH° = -3.583 kJ (for 1 mole of balanced reaction)

Step 3: Convert -9.9°C to the Kelvin scale

K = °C + 273.15 = -9.9°C + 273.15 = 263.3 K

Step 4: Calculate ΔG° at 263.3 K

ΔG° = ΔH° - T.ΔS°

ΔG° = -3.583 kJ/mol - 263.3 K × 0.51379 kJ/mol.K

ΔG° = -138.9 kJ/mol

8 0

3 years ago