O3 + M2+(aq) + H2O(l) => O2(g) + MO2(s) + 2 H+
Eo(cell) = Eo(O3/O2) - Eo(MO2/M2+)
0.44 = 2.07 - Eo(MO2/M2+)
Eo(MO2/M2+) = 1.59 V
Answer:320kelvin
Explanation:
T Kelvin=t celcius +273
T Kelvin=47+273
T Kelvin=320
Please add me to the brainleist please!!!!!
Answer:
Weathering and erosion, transportation, deposition, compaction and cementation, metamorphism, and rock melting.
Explanation:
Answer:
4.1 × 10⁻⁵ M
Explanation:
Let's consider the following balanced equation.
FeCl₃(aq) + 3 AgNO₃(aq) → 3 AgCl(s) + Fe(NO₃)₃(aq)
We can establish the following relations:
- The molar mass of AgCl is 143.32 g/mol.
- The molar ratio of AgCl to FeCl₃ is 3:1.
When 3.5 mg of AgCl are collected, the moles of of FeCl₃ that reacted are:
![3.5 \times 10^{-3} gAgCl.\frac{1molAgCl}{143.32gAgCl} .\frac{1molFeCl_{3}}{3molAgCl} =8.1 \times 10^{-6} molFeCl_{3}](https://tex.z-dn.net/?f=3.5%20%5Ctimes%2010%5E%7B-3%7D%20gAgCl.%5Cfrac%7B1molAgCl%7D%7B143.32gAgCl%7D%20.%5Cfrac%7B1molFeCl_%7B3%7D%7D%7B3molAgCl%7D%20%3D8.1%20%5Ctimes%2010%5E%7B-6%7D%20molFeCl_%7B3%7D)
The sample has a volume of 200 mL (0.200 L). The molar concentration of FeCl₃ is:
![\frac{8.1 \times 10^{-6} molFeCl_{3}}{0.200L} =4.1 \times 10^{-5}M](https://tex.z-dn.net/?f=%5Cfrac%7B8.1%20%5Ctimes%2010%5E%7B-6%7D%20molFeCl_%7B3%7D%7D%7B0.200L%7D%20%3D4.1%20%5Ctimes%2010%5E%7B-5%7DM)