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sergij07 [2.7K]
3 years ago
9

What is the difference between hot and cold atoms?

Chemistry
1 answer:
lesya [120]3 years ago
6 0
In hot water the molecules move faster versus In cold water they move slower (hope that helps)
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What is the density (in g/L) of a gas with
viva [34]

Answer:

2.22 g/L

Explanation:

There's a relationship using the ideal gas law between molar mass and density: MM=\frac{dRT}{P}, where MM is the molar mass, d is the density, R is the gas constant, T is the temperature, and P is the pressure.

We know from the problem that MM = 32.49 g/mol, T = 458 Kelvin, and P = 2.569 atm. The gas constant, R, in terms of the units atm and Kelvin is 0.08206. Let's substitute these values into the formula:

MM=\frac{dRT}{P}

32.49g/mol=\frac{d*0.08206*458K}{2.569atm}

Solve for d:

d * 0.08206 * 458 K = 32.49 * 2.569

d = (32.49 * 2.569) / (0.08206 * 458 K) ≈ 2.22 g/L

The answer is thus 2.22 g/L.

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Which of the following happens during an endothermic chemical change? (5 points)
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A, heat is absorbed
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3 years ago
Choose one metal from the reactivity series that will react safely with dilute sulphuric acid
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Answer:

Zinc (Zn) will safely react with dilute sulphuric acid.

Explanation:

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In ____________, electrons are gained by atoms and lost by others
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In ions atoms lose and gain electrons
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A rock is believed to have been formed 1.25 billion years ago, as calculated by using potassium-40 dating. If the half-life of p
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Answer:

The answer to the question is

50 % of the original amount of potassium 40 will be left after one half life or 1.25 billion years

Explanation:

To solve the question we note that the half life is the time for half of the quantity of  substance that undergoes radioactive decay to  disintegrate, thus

we have

half life of potassium 40 K₄₀ = 1.25 billion years

To support the believe tht the rock was formed 1.25 billion years ago we have

N_{(t)} =N_{(0)} (\frac{1}{2}) ^{\frac{t}{t_{\frac{1}{2} } } }

After 1.25 billion years we have

N_{(t)} =N_{(0)} (\frac{1}{2}) ^{\frac{1.25billion}{1.25 billion}  } } }  = N_{(t)} =N_{(0)} (\frac{1}{2}) ^{1 } } } =0.5 of N_{(0)} will be left or 50 % of the original amount of potassium 40 will be left

4 0
4 years ago
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