Volume of a cylinder = π r² h
Let us assume the following values:
radius = 9
height = 10
Volume = 3.14 * 9² * 10
= 3.14 * 81 *10
Volume = 2,543.40
Changes:
radius is reduced to 2/9 of its original size = 9 x 2/9 = 2
height is quadrupled = 10 x 4 = 40
Volume = π r² h
= 3.14 * 2² * 40
= 3.14 * 4 * 40
Volume = 502.40
Original volume = 2543.40 V.S. Volume after change = 502.40
The volume of an oblique cylinder decreased when its radius was decreased to 2/9 of its original size and its height is increased 4 times.
Each method works diffrently the angles inside them is what matters.
Answer:
Geary street :D
they intersect here
click on the photo. it's not a link it's a screenshot of where they intersect
Answer:
c) 
Step-by-step explanation:
−2 = −⅔[5] + b
−3⅓
1⅓ = b
y = −⅔x + 1⅓
Then convert to Standard Form:
y = −⅔x + 1⅓
+⅔x + ⅔x
__________
⅔x + y = 1⅓ [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]
3[⅔x + y = 1⅓]

* 1⅓ = 4⁄3
I am joyous to assist you anytime.