
Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
━═━═━═━═━═━═━═━═━━═━═━═━═━═━
Answer:
8p^3(2p - 3) is the factor
Step-by-step explanation:
Answer:
The mode is the least used of the measures of central tendency
Step-by-step explanation:
Consider the converses:
a) If two planes have no points in common, then they are parallel. (true)
b) If a point lies on the y-axis, then it has x-coordinate 0. (true)
c) If two angles have the same measure, then they are congruent. (true)
d) If a figure has four sides, then it is a square. (FALSE) (A figure with 4 sides may not even be a plane figure.)
The lines whose equations are given intersect at. (4, 0)