The answer is e = -2
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Step by step solution :
Step 1 :
Pulling out like terms :
1.1 Pull out like factors :
2e + 4 = 2 • (e + 2)
Equation at the end of step 1 :
Step 2 :
Equations which are never true :
2.1 Solve : 2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
2.2 Solve : e+2 = 0
Subtract 2 from both sides of the equation :
e = -2
Answer:
40.6%
Step-by-step explanation:
discount percentage:
x/y*100
266/655 *100 which is 40.6%
Hope this helps plz hit the crown :D
Answer:
It is 91% more likely that the tree was atmost 500 yards from the river.
<h3>Step-by-step explanation:</h3>
We are given with distance and height of 100 young trees near a river.
From that table, in total there are 55 trees which grow more than 3 ft during the year.
And among those 55 trees, 50 trees are atmost 50 yards from river.
Hence it is ≈91% more likely that the tree was atmost 50 yards from the river.
Answer:
Step-by-step explanation:
Hi there,
The graph indicated is showing a horizontal asymptote. In fact, it is showing both a horizontal and a <em>vertical </em>asymptote.
To tell which type it is, notice where the graph "shoots off" and almost forms an imaginary straight line in one direction. Using this logic, the horizontal asymptote will be exactly horizontal, parallel to x-axis, and vertical asymptote will be exactly vertical, parallel to y-axis.
With this graph, we notice the horizontal asymptote is at y=0, where the x-axis is. The vertical asymptote is bit more difficult to determine graphically, but can definitely say it is past x=-10. We could determine it if we had the function, but that is not necessary for this question.
Study well, and persevere. If you liked this solution, leave a Thanks or give a rating!
thanks,
Answer:
7 stickers on each page.
Step-by-step explanation:
We start with 62 stickers.
Then we give 6 to the little sister, so we subtract 6 from 62.
62-6=56
Then we divide the remaining 56 stickers evenly across 8 pages.
56/8=7
7 stickers on each page.