The mass of the bullet moving at the given values of velocity and kinetic energy is 6.4 × 10⁻⁴ kilogram.
<h3>What is Kinetic Energy?</h3>
Kinetic energy is simply a form of energy that a particle or object possesses due to its motion.
It is expressed as;
K = (1/2)mv²
Where m is mass of the object and v is its velocity.
Given the data in the question;
- Velocity of the bullet v = 970m/s
- Kinetic energy of the bullet K = 3.0 × 10³J = 3000kgm²/s²
- Mass of the bullet m = ?
We substitute our given values into the expression above.
K = (1/2)mv²
3000kgm²/s² = 0.5 × m × (970m/s)²
3000kgm²/s² = 0.5 × m × 940900m²/s²
3000kgm²/s² = m × 470450m²/s²
m = 3000kgm²/s² ÷ 470450m²/s²
m = 0.00064kg
m = 6.4 × 10⁻⁴kg
Therefore, the mass of the bullet moving at the given values of velocity and kinetic energy is 6.4 × 10⁻⁴ kilogram.
Learn more about kinetic energy here: brainly.com/question/12669551
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Terabytes. 1 terabyte is equal to 1,000 gigabytes
Potential energy is the greatest when the the kinetic energy is the least. This occurs when the ball loses the energy to fly higher, and begins to fall back to the ground.
Answer:
14.7 m
Explanation:
It would fall 14.7 m in 3 s . You multiply 4.9 by 3.
Answer:
A: 15 m/s
B: 900 Meters
Explanation:
A. Average speed is equal to final velocity plus initial velocity divided by two
Va= (20+10)/2 = 15 m/s
B.
distance = speed × time
D= 15 m/s * 60s = 900 Meters