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zaharov [31]
3 years ago
6

Which SPF level should a person look for in sunscreen as part of planning a day at the beach? pls i need it now

Physics
1 answer:
slega [8]3 years ago
3 0

30

Hope you do well on the test and hope this helps!

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Iron + Hydrochloric acid --> ?
marusya05 [52]
<h3>Iron - Fe</h3>

<h3>Hydrochloric Acid- HCl</h3>

<h2><u>Solution</u></h2>

\bold{Fe  +2HCl \rightarrow FeCl _{}{ \tiny2}  + H{ \tiny{2}}}

\therefore \bold{\fbox{{Balanced}}}

Iron + Hydrochloric Acid \rightarrow Ferrous Chloride + Hydrogen

<h2>Hope This Helps You ❤️</h2>
8 0
2 years ago
Read 2 more answers
A projectile is launched straight upwards at 75 m/s. Three seconds later, its velocity is...?
yawa3891 [41]

Answer:

V = V0 + a t

V = 75 - 9.8 * 3 = 45.6 m/s

4 0
2 years ago
A 927 g mass is connected to a light spring of force constant 5 N/m that is free to oscillate on a horizontal, frictionless trac
liraira [26]

Answer:

2.7 s

Explanation:

The period of the motion of a massless loaded spring is given by

T = 2\pi\sqrt{\dfrac{m}{k}}

where m is the mass of the load and k is the force or spring constant.

Using values in the question and converting to appropriate units,

T = 2\pi\sqrt{\dfrac{927\times10^{-3}\text{ kg}}{5 \text{ N/m}}}= 2.7\text{ s}

5 0
2 years ago
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Sixty identical drippers, each with a hole of diameter 1.00 mm, are used to water a yard. If the water in the main pipe of diame
VashaNatasha [74]

Answer:

a

   V =  5.30 *10^{-2} \ m^3

b

   v_1 = 0.3127 \ m/s

Explanation:

From the question we are told that

   The number of identical drippers is  n =  60

   The diameter of each hole in each dripper is  d =  1.0 \  mm =  0.001 \  m  

   The diameter of the main pipe is  d_m  =  2.5 \  cm  =  0.025 \  m

    The speed at which the water is flowing is  v  =  3.00 \  cm/s =  0.03 \  m/s

Generally the amount of water used in  one hour = 3600 seconds is mathematically represented as

          V =  A *  v  *  3600

Here A is the area of the main pipe with value

         A =  \pi  * \frac{d^2}{4}

=>       A = 3.142   * \frac{0.025^2}{4}

=>        A =  0.0004909 \  m^2

So  

=>   V =  0.0004909  *  0.03  *  3600

=>  V =  5.30 *10^{-2} \ m^3

Generally the area of the drippers is mathematically represented as

       A_1=  n  * \pi \frac{d^2}{4}

=>    A_1 =  60   * 3.142 *  \frac{0.001 ^2}{4}

=>    A_1 =  4.713 *10^{-5} \  m^2

Generally from continuity equation we have that  

         Av =  A_1 v_1

=>      0.0004909 *  0.03 =  4.713 *10^{-5} *  v_1

=>   v_1 = 0.3127 \ m/s

   

     

3 0
3 years ago
What is the Density of the rock?
Sindrei [870]
Your answer is gone be 3
4 0
3 years ago
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