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slamgirl [31]
3 years ago
8

Find the value of each variable

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
7 0
X is 8
y is 11.31
hope this helps
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Explain how to multiply square roots
Dmitry_Shevchenko [17]

Answer:

To multiply square roots, first multiply the radicands, or the numbers underneath the radical sign. If there are any coefficients in front of the radical sign, multiply them together as well. Finally, if the new radicand can be divided out by a perfect square, factor out this perfect square and simplify it.

Step-by-step explanation:

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4 years ago
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At the yard sale,3\4 of items for sale were toys and 5\6 of the items for sale were books Were there more toys of books for sale
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Answer:

No, the books had more sales by 5/6 being bigger (Greater Than) than 3/4.

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4 years ago
Helpppppppppppppppppppppppppppppp
Diano4ka-milaya [45]
In this case it is to find the roots of the polynomial.
 We have then:
 2x ^ 2-5x + 1 = 3
 Rewriting:
 2x ^ 2-5x-2 = 0
 Applying resolver we have
 x = (- b +/- root (b ^ 2 - 4ac)) / (2a)
 Substituting values:
 x = (- (- 5) +/- root ((- 5) ^ 2 - 4 (2) (- 2))) / (2 (2))
 x = (- (- 5) +/- root ((25 + 16)) / (2 (2))
 x = (5 +/- root (41))) / (4)
 x = ((5/4) +/- (root (41)) / 4)
 Answer:
 x = ((5/4) +/- (root (41)) / 4)
 (option 4)
8 0
4 years ago
You need to arrange eight of your favorite books along a small shelf. How many different ways can you arrange the​ books, assumi
satela [25.4K]

Answer: 40, 320 ways

8!= 8*7*6*5*4*3*2*1

3 0
4 years ago
New York City is the most expensive city in the United States for lodging. The mean hotel room rate is per night (USA Today, Apr
kow [346]

Answer:

P(X

Step-by-step explanation:

Assuming a mean of $204 per night and a deviation of $55.

a. What is the probability that a hotel room costs $225 or more per night (to 4 decimals)?

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean"

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the cost per night at the hotel, and for this case we know the distribution for X is given by:

X \sim N(204,55)  

Where \mu=204 and \sigma=55

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

We are interested on this probability

P(X>225)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>225)=P(\frac{X-\mu}{\sigma}>\frac{225-\mu}{\sigma})

=P(Z>\frac{225-204}{55})=P(Z>0.382)

And we can find this probability on this way:

P(Z>0.382)=1-P(Z

8 0
3 years ago
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