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3 years ago

Which teacher exhibited the most variable year to year performance over this 5 year span?

Mathematics

1 answer:

kupik [55]3 years ago

3 0

Please provide the graph that represents the performance of the teacher over the span of 5 years.

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Solve the following equation for y.<br>x-5y=-18<br>

olganol [36]

Answer:

y=15x+185

Step-by-step explanation:

Step 1: Add -x to both sides.

x−5y+−x=−18+−x

−5y=−x−18

Step 2: Divide both sides by -5.

−5y−5=−x−18−5

y=15x+185

6 0

3 years ago

Christen sells boxes of cookies for $4 each. Rafael sells boxes of cookies for $7 each. Each of them sold the same dollar amount

KATRIN_1 [288]

Answer:

28$ and christen sold 7 boxes while Rafael sold 4

Step-by-step explanation:

lower common multiple so take 4 x 7 = 28 as then take the 28 and divide by how much Christen gets a box which is 4 and 28 divided by 4 is 7

3 0

3 years ago

Read 2 more answers

The expression below is the factorization of what trinomial?

Lapatulllka [165]

The answer is: [A]: 45x² + 81x + 36 .
_________________________

Explanation: Use "FOIL" technique: (First, Outer, Inner, and Last Terms);
then, combine the "like terms", to simplify.
__________________________________________

(5x+4)(9x+9) = 45x² + 45x + 36x + 35 = 45x² + 81x + 36 .
(which is answer choice: "A".).
________________________________________________

6 0

3 years ago

I need 50 gallons of milk replacer for calves and the powder mixture says it's 6.25 oz for 5 gallons how many oz of powder do I

zubka84 [21]

Answer:

62.5 oz

Step-by-step explanation:

We can use the ratio proportion method:

x:50::6.25:5

x = (50x6.25)/5

OR a more simple method is to do this:

5 gallons of milk require 6.25 oz. How many oz of powder do I need to get 10x that amount? Since 50 is 10x5, you do the same thing for 6.25, and get 62.5

3 0

2 years ago

(x^2 - x^(1/2))/(1-x^(1/2))

Levart [38]

$\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 } } \right) }{ \left( 1-{ x }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot 1$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot \frac { \left( 1+\sqrt { x } \right) }{ \left( 1+\sqrt { x } \right) }$

$\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }$

$\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\} }{ \left( 1-x \right) }$

$\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }\left( 1+{ x }^{ \frac { 2 }{ 2 } } \right) -x$

$\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }-{ x }^{ \frac { 3 }{ 2 } }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x$

3 0

3 years ago

Read 2 more answers