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Illusion [34]
3 years ago
12

Which of the functions graphed below is continuous?

Mathematics
2 answers:
artcher [175]3 years ago
6 0

Answer:

the first one

Step-by-step explanation:

because the slope for the second one has no follow of origin

Gelneren [198K]3 years ago
6 0

Answer:

all of them except the last one

Step-by-step explanation:

because the last one is 2 lines, so it is not continuous, not sure btw

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<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

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