EQ. 1: x + y = 8
EQ. 2: 4x-y = 7
Rewrite EQ. 1 as EQ. 3: x = 8-y
Replace x in EQ.2 with EQ. 3:
4(8-y) - y = 7
Use the distributive property:
32 - 4y - y = 7
Combine like terms:
32 - 5y = 7
Subtract 32 from each side:
-5y = -25
Divide both sides by -5
y = -25 / -5
y = 5
Now replace y with 5 in EQ. 3 to solve for X:
x = 8-5
x = 3
The point of intersection is X = 3, Y = 5, which is written as (3,5)
That's simplied already, unless they want a decimal then it's .6 or something
Answer:
0
Step-by-step explanation:
The only value that would make sense is if at least one of the variables (A , B , C , D) is 0 (if not all of them). When multiplied, the answer will still be 0, thereby making the equation true.
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Answer:
absolutley no solutions
Step-by-step explanation:
Since we know that a - 2 will equal 8, it is safe to assume that 8 + 2 = 10. Therefore a=10.
