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Marizza181 [45]
3 years ago
7

How far apart are the foci of an ellipse with a major axis of 20 feet and a minor axis of 14 feet?

Mathematics
1 answer:
omeli [17]3 years ago
3 0
The solution for this question is simple. First we need to divide both numbers by 2 which will give us 10 and 7. This is the equation x^2/10^2 + y^2/7^2 = 1sqrt(100-49) = 7.14 (the answer do not have a perfect square root)
Foci are 14.28 units apart 
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Answer:

3ab

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(b+a)

Step-by-step explanation:

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1/a^2 - 1/b^2

Multiply the top and bottom by a^2 b^2/ a^2/b^2 to clear the fractions

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-------------------

(1/a^2 - 1/b^2) a^2b^2

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b^2 -  a^2

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b^2 -  a^2

The bottom is the difference of squares

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(b-a) (b+a)

Cancel like terms from the top and bottom

3ab

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