How far apart are the foci of an ellipse with a major axis of 20 feet and a minor axis of 14 feet?

1 answer:

3 0

The solution for this question is simple. First we need to divide both numbers by 2 which will give us 10 and 7. This is the equation x^2/10^2 + y^2/7^2 = 1sqrt(100-49) = 7.14 (the answer do not have a perfect square root)
Foci are 14.28 units apart

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ruben is buying bricks for a project. he knows that 5 bricks weigh 26 1/4. he wants to know the weight of 24 bricks

Phoenix [80]

Answer:

the weight of 24 bricks is :

$124\frac{4}{5}$

Step-by-step explanation:

$26\frac{1}{4} =26+\frac{1}{4} =\frac{26\times 4}{4} +\frac{1}{4} =\frac{105}{4}$

It is clear that there is a proportional relationship between the number of bricks and their weights then :

$\frac{26\frac{1}{4} }{5} =\frac{x}{24} \Longrightarrow \frac{\left( \frac{105}{4} \right) }{5} =\frac{x}{24} \Longrightarrow \frac{26}{5} =\frac{x}{24}$