We have to set up 2 different equations if we are to solve for 2 unknowns. The first equation is x = y + 4. One number (x) is (=) 4 more than another (y + 4). Since we have determined that x is larger (cuz it's 4 more than y), when we set up their difference, we are going to subtract y from x cuz x is bigger. The second equation then is
. In our first equation we said that x = y + 4, so let's sub that value in for x in the second equation:
. Expand that binomial to get
. Of course the y squared terms cancel each other out leaving us with 8y + 16 = 64. Solving for y we get that y = 6. Subbing 6 in for y in our first equation, x = 6 + 4 tells us that x = 10. Yay!
Answer:
Part A)
The number of marbles that Su has at the beginning is 
The number of marbles that Bertha has at the beginning is 
Part B)
The number of marbles that Su has at the end is 
The number of marbles that Bertha has at the end is
Step-by-step explanation:
Let
x------> number of marbles that Su has at the beginning
y------> number of marbles that Bertha has at the beginning
we know that
----> equation A
----> equation B
substitute equation A in equation B
Find the value of x
Part A) How many marbles did they EACH have at the begining?
The number of marbles that Su has at the beginning is
The number of marbles that Bertha has at the beginning is
Part B) How many did they EACH have at the end?
so
therefore
The number of marbles that Su has at the end is
The number of marbles that Bertha has at the end is
7x2.2 is 14.4 then you will need to multiply 3x2.2 then add them up
Answer:
<h2>1/3 = 5/15 and 1/5 = 3/15</h2>
Step-by-step explanation:
This is just a simple division problem. To make your life easier, make them both into improper fractions, 254/5 and 4/1. Use reciprocals to multiply. 254/5 * 1/4. Then you get 127/10, which simplifies to 12 7/10 as your answer.
I hope this helped and did not confuse you!
